Question

Please help me I’m stuck

Answer 1

Answer:

Step-by-step explanation:

use Pythagoras's   theorem  to find the hypontenuse of the isosceles triangle on the right side.

hyp = sqrt [ 5^2 + 5^2 ]

hyp = sqrt [ 50 ]

hyp = 7.0710678

now we know the adjacent side of the triangle on the left , since it's the same as the hypotenuse of the triangle on the right.

SOH CAH TOA ( to remember how the trig funct. fit on triangles)

CAH  Cos(Ф) = adj / hyp

cos(Ф) = 7.0710678 / 8

Ф = arcCos(  7.0710678 / 8 )

Ф = 27.8855668°

TOA  Tan(Ф) = x / 7.0710678

Tan( 27.8855668° ) =  x / 7.0710678

7.0710678 * Tan( 27.8855668° ) = x

3.741657 = x

x = 3.7  ( to the nearest 10th )

Answer 2

Answer:

$x = 3.7$

Step-by-step explanation:

We can find the side of the hypotenuse by applying pythagorean theorem.

${5}^{2} + {5}^{2} = {x}^{2}$

$25 + 25 = {x}^{2}$

$50 = {x}^{2}$

$x = 5 \sqrt{2}$

Now we can apply pythagorean theorem on the other triangle

$(5 \sqrt{2} ) {}^{2} + {x}^{2} = {8}^{2}$

$50 + {x}^{2} = 64$

${x}^{2} = 14$

$x = \sqrt{14}$

$x = 3.7$