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Sati [7]
3 years ago
7

during a 2 hour trip,a family is able to travel 140 kilometers. what is the average speed of the family during this portion of t

his trip?

Chemistry
1 answer:
TiliK225 [7]3 years ago
5 0

The average speed of the family : 70 km/h

<h3>Further explanation</h3>

Given

time = 2 hour

distance = 140 km

Required

The average speed

Solution

Distance is the length traveled by an object within a certain time  

Average speed = total distance/total amount of time

Can be formulated :

 Avg speed = d : t

Total distance traveled : 140 km

Total time : 2 hr

Avg speed = 140 : 2 = 70 km/h

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How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.
Marysya12 [62]

4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:  

We will start with the Molarity  

\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L  

Equation for solving mole of solute

\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

0.750 \times 0.0375=0.0281

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

0.028 \times 166=4.648

So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.

8 0
3 years ago
How many liters of salt solution will be needed to provide 15 grams of salt if the concentration of the solution is 50 g/l?​
asambeis [7]

Answer:

.30 l

Explanation:

15g/50g/l= .3l

6 0
3 years ago
PLEASE HELP ME (JOULES)
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Answer:

The answer is not 9.9 i used that and got it wrong

Explanation:

8 0
2 years ago
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jeka94
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3 years ago
For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = -20.5 kJ/mol?
harina [27]

Answer:

Q= 245 =2.5 * 10^2

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ΔG = ΔGº + RTLnQ, so also ΔGº= - RTLnK

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ΔGº= - RTLnK = - 6659.3 J/mol = - 6.7 KJ/mol

ΔG = ΔGº + RTLnQ → -20.5KJ/mol = - 6.7 KJ/mol + 2.5KJ/mol* LnQ

→ 5.5 = LnQ → Q= 245 =2.5 * 10^2

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3 years ago
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