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3 years ago

Find the weight of HNO_3 present in 20ml, 0.30 N

Chemistry

1 answer:

yanalaym [24]3 years ago

6 0

Answer:

mass of HNO₃ = 0.378 g

Explanation:

Normality = Molarity * number of equivalents

Molarity = Normality/number of equivalents

normality of HNO₃ = 0.30 N, Volume = 20 mL

HNO₃ ionizes in the following way:

HNO₃(aq) ----> H⁺ + NO₃⁻

Therefore, number of equivalents for HNO₃ is 1

molarity of HNO₃ = 0.30/1 =0.30 mol/dm³

Using the formula, molarity = number of moles/volume in liters

number of moles = molarity * volume

Number of moles of HNO₃ = 0.30 mol/dm³ * 20ml * 1 dm³ /1000 mL

number of moles = 0.006 moles

From the formula, mass = number of moles * molar mass

molar mass of HNO₃ = 63.0 g/mol

mass = 0.006 * 63

mass of HNO₃ = 0.378 g

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A horizontal pipe 15 cm in diameter and 4 m long is buried in the earth at a depth of 20 cm. The pipe-wall temperature is 75 deg

Basile [38]

Explanation:

The given data for case (1) is as follows.

h = 20 cm = 0.2 m

Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.

Q = $kA \frac{\Delta T}{L}$

where, A = area

L = length

k = thermal conductivity = 0.8 W/m

$\Delta T$ = change in temperature.

Therefore, putting the given values into the above formula as follows.

Q = $kA \frac{\Delta T}{L}$

= $0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{0.2}$

= 168 W

For case (2), h = 180 cm = 1.8 m

Therefore, heat lost will be calculated as follows.

Q = $kA \frac{\Delta T}{L}$

= $0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{1.8}$

= 18.67 W

Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.

8 0

3 years ago

What does E=mc^2 mean

Brums [2.3K]

E represents units of energy, m represents units of mass, and c2 is the speed of light squared, or multiplied by itself

So I THINK that A is the right answer but i may be wrong.

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8 0

3 years ago

A buret is filled with 0.1517 M A 25.0 mL portion of an unknown acid and two drops of indicator are added to an Erlenmeyer flask

erik [133]

Answer:

Molarity of Unknown Acid = 0.1332 M

Explanation:

Data for solving problem:

Molarity of base in buret (M₁)= 0.1517 M

volume of the acid in Erlenmeyer flask (V₂)= 25.0 mL

Volume of the base in the buret (V₁) = final volume of buret - initial volume in buret

final volume of buret = 22.5 mL

initial volume in buret = 0.55 mL

Volume of the base in the buret (V₁) = 22.5 mL -0.55 mL = 21.95 mL

Volume of the base in the buret (V₁) = 21.95 mL

Molarity of Unknown acid in the Erlenmeyer flask (M₂) = To be find

Explanation:

It is acid base titration and formula for this titration is as follows:

Molarity of base x Volume of base = Molarity of acid x volume of acid

it can be written as

M₁V₁ = M₂V₂ -------------------- equation (1)

we have to find M₂

so by rearrangment the equation (1)

M₁V₁ / V₂ = M₂ ------------------ equation (2)

put the values in equation in equation (2)

M₂ = 0.1517 M x 21.95 mL / 25.0 mL

M₂ = 3.3298 /25.0

M₂ = 0.1332 M

so the Molarity of Unknown acid is <u>0.1332 M</u>

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3 years ago

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salantis [7]

Answer:

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7 0

3 years ago

Read 2 more answers

How many moles of Co2 are produced when 0.2 moles of sodium carbonate reacts with excess HCl

Pie

To determine the number of moles of carbon dioxide that is produced, we need to know the reaction of the process. For the reaction of HCl and sodium carbonate, the balanced chemical equation would be expressed as:

2HCl + Na2CO3 = 2NaCl + H2O + CO2

From the initial amount given of sodium carbonate and the relation of the substances from the balanced reaction, we calculate the moles of carbon dioxide as follows:

0.2 moles Na2Co3 ( 1 mol CO2 / 1 mol Na2Co3 ) = 0.2 moles CO2

Therefore, the amount in moles of carbon dioxide that is produced from 0.2 moles sodium carbonate would be 0.2 moles as well.

5 0

3 years ago