Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
To find the equation take the slope 2/3
y-y(1)=m(x-x(1)
y-4=2/3(x-8) = 2/3x-16/3
Next solve for y
y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator)
y=2/3x-16/3 + 12/3
y=2/3x-4/3
A.) m=5/6
B.) y
=5/6x-3 use the slope formula y=mx+b
C.) y
-y1 = m(x-x1)
Answer:
3x+y=43
Step-by-step explanation:
because
ML~=SR
43=43
