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Andreyy89
3 years ago
10

Three points A, B and C are located along a horizontal line. A positive test charge is released from rest at C and accelerates t

owards B. Upon reaching B, the test charge continues to accelerate toward A. Assuming that only motion along the line is possible,
a) Which point has the highest potential; A, B or C?

b) What will a negative test charge do when it is released from rest at B?​
Physics
1 answer:
iVinArrow [24]3 years ago
4 0
B is the answer hope this helps with the time bus boy
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An empty capacitor is capable of storing 1.0 × 10-4 J of energy when connected to a certain battery. If the distance between the
dangina [55]

Answer:

Explanation:

Energy stored in a capacitor

= 1/2 C₁V²

capacity of a capacitor

c = εK A / d

k is dielectric and d is distance between plates .

When  the distance between the plates is halved and then filled with a dielectric (κ = 4.3)

capacity becomes 4.3  x 2 times

New capacity

C₂ = 8.6 C₁

Energy of modified capacitor

1/2 C₂ V²= 1/2 x 8.6 c x V²

Energy becomes

8.6 times.

Energy stored = 8.6 x 10⁻⁴ J

3 0
3 years ago
Which equation represents a neutralization reaction?
JulijaS [17]
Option B: acid+base->water+salt is the equation represents a neutralization reaction.
6 0
2 years ago
it takes 1.4 minutes for Jonny to get to class which is a distance of 82 meters away s. what is Johnny’s average speed in second
Marat540 [252]
We have to use the equation speed=distance/time.
We want the average speed in second so we have to change the minutes into seconds. We can do this by multiplying the minutes by 60 (60seconds in 1 minute). 60x1.4= 84 seconds.
Speed=distance/time, distance is 82 and time is 84 so speed=82/84
Average speed = 0.98ms^-1 (2dp)
4 0
4 years ago
A mosquito of mass 0.15 mg is found to be flying at a speed of 50 cm/s with an uncertainty of 0.5 mm/s. (a) How precisely may it
amid [387]

Answer:

a) Δx = t 0.05 + 0.5

,  Δx = 0.5 cm, b)  Do not present any problem

Explanation:

The kinematic equation for constant speed is

          v = x / t

          x = v t

a) the uncertainty can be calculated with

          Δx = dx /dv Δv + dx /dt Δt

          Δx = t Δv + v Δt

Speed ​​is

         v = (50.00 ± 0.05) cm / s

     

The most common uncertainty for the time of Δt = 0.01 s

    We replace

           Δx = t 0.05 + 50 0.01

           Δx = t 0.05 + 0.5

We must know the time to have an explicit value, if we assume that the measure was t = 1s

           Δx = 0.5 cm

b)

Do not present any problem since its value is not very small, we must take as soon as the quantum effects and the velocity are not so high that we must take into account the relativistic effects

5 0
3 years ago
Luke Autbeloe drops an approximately 5.0 kg object (weight = 50.0 N) off the roof of his house into the swimming pool below. Upo
Murljashka [212]

Answer:

Graph B represents correct graph for velocity time

Explanation:

Initially the object is dropped under the influence of constant force due to gravity

So here we can say its acceleration is constant due to gravity

hence here the velocity will increase downwards due to gravity and it is given as

v = 0 + (-10)t

now when it enters into the pool an upward force of same magnitude will act on it

so net force on it is

F = 50 - 50 = 0

so here we will have no acceleration and it will move with constant speed after that

so here correct graph is

Graph B

6 0
4 years ago
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