Question

A boy and a girl are riding a merry- go-round which is turning ata constant rate. The boy is near the outer edge, while a girl is closer to the center. Who has the greater tangential acceleration? 1. the boy 2. the girl 3. both have zero tangential 25% try penalty acceleration Hints: 0,0 4. both have the same non-zero tangential acceleration

Answer 1

Answer:

The correct answer is

1. the boy 2.

Explanation:

Since Tangential acceleration = v²/r  then the

v = ωr and v² =  ω²r² then the tangential acceleration = ω²r²/r = ω²r

This shows that  since ω is the same for both of them, the boy with greater r has the most acceleration.

The tangential acceleration $a_t =$ α·r