Answer : The correct option is, (d) 90 mL
Explanation :
First we have to calculate the volume of an object.
As we know that,
Given:
Density of an object = 0.25 g/mL
Mass of an object = 10 g
Now put all the given values in the above formula, we get:
Thus, the volume of an object is 40 mL.
Now we have to calculate the height of the water in the graduated cylinder rise.
As we are given that:
The volume of water in graduated cylinder = 50 mL
The volume of an object = 40 mL
The height of the water in the graduated cylinder rise = Volume of water in graduated cylinder + Volume of an object
The height of the water in the graduated cylinder rise = 50 mL + 40 mL
The height of the water in the graduated cylinder rise = 90 mL
Therefore, the height of the water in the graduated cylinder rise will be, 90 mL
I think that the girl has greater tangential acceleration because she is closer to the center and the acceleration is greater there.
Answer: so when a turbine converts the K.E and the potential of any moving fluid (more likely liquid or gas) to energy. once the proc is started the turbine generato, the fluid such as water, steam, combus gasses, or air pushes s big series of blades that have mounted on a shaft, which then will rotate the shaft that’s conn to the generator
Explanation: hope this helped plz mark brainest