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attashe74 [19]
3 years ago
10

Question 25

Physics
1 answer:
Aleks04 [339]3 years ago
7 0
The answer would be B
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. On a safari, a team of naturalists sets out toward a research station located 9.6 km away in a direction 42° north of east. Af
Elden [556K]

Answer:\theta =49.76^{\circ} North of east

Explanation:

Given

Research station is 9.6 km away in 42^{\circ}North of east

after travelling 3.1 km 25^{\circ} north of east

Position vector of safari after 3.1 km is

r_2=3.1cos25\hat{i}+3.1sin25\hat{j}

Position vector if had traveled correctly is

r_0=9.6cos42\hat{i}+9.6sin42\hat{j}

Now applying triangle law  of vector addition we can get the required vector(r_1)

r_1+r_2=r_0

r_1=(9.6cos42-3.1cos25)\hat{i}+(9.6sin42-3.1sin25)\hat{j}

r_1=4.325\hat{i}+5.112\hat{j}

Direction is given by

tan\theta =\frac{y}{x}=\frac{5.112}{4.325}

\theta =49.76^{\circ}

8 0
3 years ago
2) A man squeezes a pin between his thumb and finger, as shown in Fig. 6.1.
Salsk061 [2.6K]
<h3>pressure = force / area</h3>

<h3>force = 84 N</h3><h3>pressure = 6 × 10 - 5 = 55 m2</h3>

<h3>pressure = 84 / 55</h3>

<h3>pressure = 1.53 pascals</h3>

hope that helps and please tell me if i am wrong :)

8 0
3 years ago
Approximately how far is the sun from the center of the milky way galaxy?
enot [183]
The sun is approximately 27,000 light years away from the center of our galaxy.
8 0
3 years ago
Read 2 more answers
Hi there! Can someone help me out please?
Eva8 [605]
Hello, some examples are Earth science, chemistry and Navigation science (don't know if there is called in this way).

In Earth Science we can talk about Geomagnetism.

In Chemistry, electrostatics and electrochemistry.

In Navigation science the compass.

Hope it helped.
6 0
3 years ago
A car weighing 9800 N travels at 30 m/s. What braking force brings it to rest in 100m? In 10 m?
Svetach [21]

As per kinematics equation we know that

final speed of the car = 0 m/s

initial speed is given as 30 m/s

distance moved = 100 m

now we have

v_f^2 - v_i^2 = 2 a d

0 - 30^2 = 2(a)(100)

a = - 4.5 m/s^2

now braking force is given as

F = ma

now for mass we know that the weight of car is

W = mg = 9800 N

so mass of car is

m = 1000 kg

now we have

F = 1000(4.5) = 4500 N

Part b)

Again we have

final speed of the car = 0 m/s

initial speed is given as 30 m/s

distance moved = 10 m

now we have

v_f^2 - v_i^2 = 2 a d

0 - 30^2 = 2(a)(10)

a = - 45 m/s^2

now braking force is given as

F = ma

mass of car is

m = 1000 kg

now we have

F = 1000(45) = 45000 N

4 0
3 years ago
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