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Harlamova29_29 [7]
3 years ago
15

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

advertising expenditures for 63 manufacturing companies located in the Southwest. The mean expense is $50.63 million and the standard deviation is $11.48 million. Is it reasonable to conclude the sample data are from a population that follows a normal probability distribution?
Mathematics
1 answer:
vredina [299]3 years ago
6 0

Answer:hi

Step-by-step explanation:

Hi

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Phillip is restoring a square tabletop he wants to finish the outside edges with a piece of decorative molding what total length
PilotLPTM [1.2K]

Answer:

8 square feet

3 0
3 years ago
What is a correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9?
Maksim231197 [3]
Hello,
 the first step should be to distribue:
-4(3-5x)= -12+20x

Teh resolution may be:

-4(3-5x)>=-6x+9
==>-12+20x>=-6x+9
==>20x+6x>=9+12
==>26x>21
==>x>=21/26

But an other way may be used:

-4(3-5x)>=-6x+9
==>3-5x<= -6x/(-4)+9/(-4)
==>-5x-3/2 x<=-9/4 -3

==>-13/2 x <=-21/4

==>x>= -21/4 *(-2/13)
==>x>=21/(2*13)
==>x>=21/26

5 0
3 years ago
Read 2 more answers
6) The amount of Jen's monthly phone bill is normally distributed with a mean of $70 and a standard
alexandr402 [8]

Answer:

i)The correct option is  D.) 99.74%

ii) The correct option is B.) 68.26%

Step-by-step explanation:

i) P(10≤X≤70) = P(  (10−40)/10  ≤Z≤   (70−40 )/10 ) =  Pr(−3≤Z≤3)

= 0.9987 - 0.0013 = 0.99734

Therefore the percentage of Jen's monthly phone bills are between $40 and $100 is D.) 99.74%

ii)P(2.1≤X≤3.1) = P(  (2.1 − 2.6) /0.5   ≤ Z  ≤ (3.1−2.6 )/0.5)  =  Pr(−1  ≤Z  ≤1) )

=  0.8413 − 0.1587  =  0.6826

Therefore the percentage of students at college have a GPA between 2.1 a,d 3.1 is B.) 68.26%

5 0
3 years ago
(04.01 MC)
Reil [10]

Answer:

144'

Step-by-step explanation:

Your ratio is 45'/5" or 9:1

9x4"=36'

9x3"=27'

45+36+36+27=144'

I believe this is the same answer as I gave previously.

4 0
3 years ago
Determine the numerical length of JK.​
Zarrin [17]

Answer:

30

So the two sectors add to the full length:

JK + IJ = IK

x+6 + 9 = 2x

Rearrange:

x=15

So the numerical length:

2x

2*15

30

5 0
3 years ago
Read 2 more answers
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