3 years ago

How far does a 1,300-kg race car travel if it accelerates from rest at a rate of 14 m/s/s for 10

Physics

1 answer:

muminat3 years ago

7 0

Answer:

700 m

Explanation:

Given:

v₀ = 0 m/s

a = 14 m/s²

t = 10 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (10 s) + ½ (14 m/s²) (10 s)²

Δx = 700 m

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3 years ago

Starting from rest, a car travels 18 meters as it accelerates uniformly for 3.0 seconds. What is the magnitude of

omeli [17]

Answer:

$a=4\frac{m}{s^2}$

Explanation:

Hello.

In this case, for this uniformly accelerated motion in which the car starts from rest at 0 m/s and travels 18 m in 3.0 s, we can compute the acceleration by using the following equation:

$x_f=x_0+v_0t+\frac{1}{2}at^2$

Whereas the final distance is 18 m, the initial distance is 0 m, the initial velocity is 0 m/s and the time is 3.0 s, that is why the acceleration turns out:

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