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Ber [7]
3 years ago
12

Please answer

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

183.6kg

Explanation:

Given parameters:

Specific heat of the substance  = 0.246J/g°C

Change in temperature  = 15.5°C

Amount of energy released  = 700J

Unknown:

Mass of the sample  = ?

Solution:

To solve this problem we used the energy equation:

        H  = m c Δt

 H is the energy released

  m is the unknown mass

  c is the specific heat

 Δt  is the change in temperature

Now insert the parameters and find m;

 700  = m x 0.246 x 15.5

  700 = 3.8m

     m  = 183.6kg

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Which of the reactions are spontaneous (favorable)? A. DHAP↽−−⇀glyceraldehyde-3-phosphateΔ????=3.8 kJ/mol B. C2H4+H2−→−−Rh(I)C2H
dalvyx [7]

Answer:

The spontaneous reactions are:

B. C_{2}H_{4} + H_{2} \overset{Rh(I)}{\rightarrow}C_{2}H_{6} ; <u>ΔG= −150.97 kJ/mol  </u>

D. C₆H₁₃O₉P + ATP ⟶ C₆H₁₄O₁₂P₂ + ADP; <u>ΔG = −14.2 kJ/mol  </u>

Explanation:  

Gibbs free energy , denoted by ΔG, is the <u>quantitative measure of the favorability or spontaneity</u> of a given process or chemical reaction that is carried out at constant temperature (T) and pressure (P).

Therefore, Gibbs free energy in J: ΔG = ΔH - TΔS

Here, ΔH is the change in enthalpy and ΔS is the change in the entropy

For a given chemical reaction to be <u>spontaneous or favorable</u>, ΔG should be negative (ΔG < 0).

A. DHAP ⇌ glyceraldehyde-3-phosphate ; <u>ΔG = 3.8 kJ/mol  </u>

<u>The value of ΔG is positive (ΔG > 0). Therefore, this reaction is not spontaneous.</u>

B. C_{2}H_{4} + H_{2} \overset{Rh(I)}{\rightarrow}C_{2}H_{6} ; <u>ΔG= −150.97 kJ/mol  </u>

 <u>The value of ΔG is negative (ΔG < 0). Therefore, this reaction is spontaneous.</u>

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C. glutamate + NAD⁺ + H₂O ⟶ NH⁴⁺ +α-ketoglutarate + NADH + H⁺ ; <u>ΔG = 3.7 kcal/mol   </u>

<u>The value of ΔG is positive (ΔG > 0). Therefore, this reaction is not spontaneous.</u>

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D. C₆H₁₃O₉P + ATP ⟶ C₆H₁₄O₁₂P₂ + ADP; <u>ΔG = −14.2 kJ/mol  </u>

 <u>The value of ΔG is negative (ΔG < 0). Therefore, this reaction is spontaneous.</u>

<u />

E. L -malate + NAD⁺ ⟶ oxaloacetate + NADH + H⁺; <u>ΔG = 29.7 kJ/mol </u>

<u>The value of ΔG is positive (ΔG > 0). Therefore, this reaction is not spontaneous.</u>

5 0
3 years ago
Why is only one diastereomer formed in this reaction? Relate your answer to the mechanism you drew. b) If you used cis-stilbene
crimeas [40]

Answer:

1. Diastereomers have different physical properties (unlike most aspects of enantiomers) and often different chemical reactivity. ... Many conformational isomers are diastereomers as well. Diastereoselectivity is the preference for the formation of one or more than one diastereomer over the other in an organic reaction.

2. The result is a trans dibromide, as shown in the equation below

Explanation:

Diastereomers (sometimes called diastereoisomers) are a type of a stereoisomer.[1] Diasteoreomers are defined as non-mirror image non-identical stereoisomers. Hence, they occur when two or more stereoisomers of a compound have different configurations at one or more (but not all) of the equivalent (related) stereocenters and are not mirror images of each other.[2] When two diastereoisomers differ from each other at only one stereocenter they are epimers. Each stereocenter gives rise to two different configurations and thus typically increases the number of stereoisomers by a factor of two.

2. the addition of bromine to the trans and

cis isomers of 1,2-diphenylethene, more commonly known as trans- and cis-stilbene.

H

H

H H

trans-stilbene cis-stilbene

m.p. 122-124°C b.p. 82-84°C

density 0.970 g/mL density 1.011 g/mL

M.W. 180.25 g/mol M.W. 180.25 g/mol

In both cases, the nucleophilic double bond undergoes an electrophilic addition reaction

by the bromine reagent which proceeds via a cyclic bromonium ion. The addition of

bromine begins at one side of the double bond (either side is equally likely, but only one

option is drawn) and is followed by attack of bromide ion on the bromonium ion (again,

attack could occur at either carbon since the ion is symmetric, but only one option is

drawn). The result is a trans dibromide, as shown in the equation below:

Since the cis and trans isomers of stilbene have different geometries, it follows

that upon reaction with bromine they give rise to stereoisomeric bromonium ions and,

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4 0
4 years ago
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mina [271]
<span>Draw the Lewis structure. Bromine has 3 bonds and two lone pairs for a trigonal bipyramidal electron geometry and an sp^3d hybridization. Fluorine is peripheral it does not require hybridization, but we often consider it to be hybridized too - it has 1 bond and 3 lone pairs for sp^3 hybridization. So the sigma bonds come from an overlap of an sp^3d orbital on Br with an sp^3 orbital on F. If you don't consider the F to be hybridized the overlap would have to be to a p orbital on the F</span>
8 0
4 years ago
There are several aromatic compounds with the formula C8H9Cl. Draw those that have a trisubstituted ring where the methyl groups
Kryger [21]

Answer:

3-Chloro-1,2-dimethylbenzene

4-Chloro-1,2-dimethylbenzene

Explanation:

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7 0
4 years ago
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Paraphin [41]

Here we have to identify the sample which need more energy to heat the sample 1 degree Celsius.

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As per the definition of specific heat of a compound, the amount of heat required to increase the temperature of the material 1 degree Celsius is the specific heat of the material.

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substance              specific heat

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Tin                                0.21

Silver                            0.235

Iron                              0.449

Calcium                        0.647

Granite                         0.803

Aluminium                   0.897

Magnesium                  1.023

From the given data lead, magnesium, iron and aluminium have the specific heat 0.129, 1.023, 0.449 and 0.897 respectively. Thus magnesium will require more energy than the others to heat.

6 0
3 years ago
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