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Brrunno [24]
3 years ago
15

One of the most recognizable corrosion reactions is the rusting of iron. rust is caused by iron reacting with oxygen gas in the

presence of water to create an oxide layer. iron can form several different oxides, each having its own unique color. red rust is caused by the formation of iron(iii) oxide trihydrate. in the space provided, write the balanced reaction for the formation of fe2o3•3h2o(s). phases are optional.
Chemistry
2 answers:
lesya692 [45]3 years ago
8 0

Answer : The balanced chemical reaction for rusting of irons is :

4Fe(s)+3O_2(g)+6H_2O(l)\rightarrow 2[Fe_2O_3(s).3H_2O(s)]

Explanation :

Iron rusting : It is a type of chemical process where an iron nail react with the water in the presence of moisture (oxygen) to give iron oxide as a product. Rusting of iron is an oxidation-reduction reaction in which iron losses electrons to oxygen atom.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

The balanced chemical reaction for rusting of irons is :

4Fe(s)+3O_2(g)+6H_2O(l)\rightarrow 2[Fe_2O_3(s).3H_2O(s)]

Half reactions of oxidation and reduction are :

Oxidation : Fe(s)\rightarrow Fe^{3+}+3e^-

Reduction : \frac{1}{2}O_2+2e^-\rightarrow O^{2-}

zloy xaker [14]3 years ago
3 0

Answer:  Fe(s) + 6H_2O(l) + 3O_2(g)  -> 4Fe(OH)_3(s)

Explanation:

The Chemical equation for the formation of rust is:

Iron + Water + Oxygen ----> Rust

4 Fe(s) + 6 H2O(l) + 3 O2(g) → 4 Fe(OH)3(s)

The Iron Hydroxide However dehydrates to produce Fe2O3 * nH2O

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now find n1
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Where was Sodium first discovered? <br> Location:<br> No copy-pasting
Verizon [17]

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Explanation:

Hope this helped!

4 0
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Read 2 more answers
Easy Chem, Will Give brainliest
Crazy boy [7]

Answer:

3.94 L

Explanation:

From the question given above, the following data were obtained:

Mass of O₂ = 5.62 g

Volume of O₂ =?

Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:

Mass of O₂ = 5.62 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 5.62 / 32

Mole of O₂ = 0.176 mole

Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.

Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP

5 0
3 years ago
What is the pH of a solution within a solution with pH = 4.50? [H +] = 3.25×10-6 M?
Lisa [10]

Answer: 5.48

Explanation:

pH is the negative logarithm of hydrogen ion concentration in a solution.

Mathematically, pH = - log(H+)

where H+ represent the concentration of hydrogen ion

So, to get the pH of the solution with [H +] = 3.25×10-6 M:

Apply, pH = -log(H+)

pH = - log (3.25×10-6 M)

pH = - ( -5.48)

(Note that the minus signs will cancel out each other)

Therefore pH = 5.48

Now we know that the pH of the solution with hydrogen ion concentration of 3.25×10-6 M is 5.48 (i.e slightly acidic)

Thus, we can finally say 5.48 is the pH of the solution within a solution with pH = 4.50

6 0
4 years ago
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