Answer:
k = 4.21 * 10⁻³(L/(mol.s))
Explanation:
We know that
k = Ae ------------------- euqation (1)
K= rate constant;
A = frequency factor = 4.36 10^11 M⁻¹s⁻¹;
E = activation energy = 93.1kJ/mol;
R= ideal gas constant = 8.314 J/mol.K;
T= temperature = 332 K;
Put values in equation 1.
k = 4.36*10¹¹(M⁻¹s⁻¹)e
k = 4.2154 * 10⁻³(M⁻¹s⁻¹)
here M =mol/L
k = 4.21 * 10⁻³((mol/L)⁻¹s⁻¹)
or
k = 4.21 * 10⁻³((L/mol)s⁻¹)
or
k = 4.21 * 10⁻³(L/(mol.s))
Answer:
a) 17.20
b) 11.31
c) 14.42
d) 12.65
Explanation:
(a)
The girl is at the origin of the x,y coordinates (i.e 0,0,0 )
the position vector of the car at time 't' secs is
at t=2s, the position vector is
Therefore, the the distance between the car and the girl is
s = 17.20
(b)
The position of the car at t = 0s is
The position of the car at t = 2s is
The distance of the car traveled in the interval from t=0s to t=2 s is as follows:
(c)
The position vector of the car at time 't' secs is
The velocity of the car is
the direction of the car's velocity at t = 2s is going to be
Thus; The speed of the car is
(d) the car's acceleration is:
The magnitude of car's acceleration at t=2s is