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3 years ago

Why is it important to always be wearing a personal flotation device (PFD) when in or around the water?

Engineering

2 answers:

oee [108]3 years ago

4 0

The correct answer is C. A PFD takes some time to fit properly especially in an emergency.

Explanation:

The purpose of a Personal Flotation Device (PFD) such as a life jacket is to keep people floating to prevent drowning. Additionally, its effectiveness depends on whether the Personal Floating Device was fitted properly. Because of this, if an activity involves being in or around water, it is important to wear a Personal Flotation Device and to fit this properly before approaching the water because it is difficult to adjust the device during an emergency. Thus, it is important to wear a PFD in or around water because this takes some time to fit properly (Option C.)

IgorLugansk [536]3 years ago

3 0

Answer:Wearing a PFD reduces the chances of capsizing your vessel

Explanation: I THINK

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Oxygen enters an insulated 14.2-cm-diameter pipe with a velocity of 60 m/s. At the pipe entrance, the oxygen is at 240 kPa and 2

MatroZZZ [7]

Answer:

Entropy generation==0.12 KW/K

Explanation:

$s_2-s_1=C_p\ln \frac{T_2}{T_1}-R\ln \frac{P_2}{P_1}$

$s_2-s_1=0.891\ln \frac{291}{293}-0.2598\ln \frac{200}{240}$

$s_2-s_1=0.0412\frac{KJ}{kg-K}$

Mass flow rate= $\rho\times\dfrac{\pi}{4}d^2V$

$\rho_1=\dfrac {P_1}{RT_1}$

$\rho_1=\dfrac {240}{0.2598\times 293}$

$\rho_1=3.51\frac{kg}{m^3}$

mass flow rate= $\rho_1A_1V_1$

So by putting the values

Mass flow rate=2.97 kg/s

So entropy generation=(2.97)(0.0412)

=0.12 KW/K

8 0

4 years ago

What kind of robot should i make

schepotkina [342]

Answer:

It really depends on what you want it to do. I would make one that does chores around the house so I don't have to.

Explanation:

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2 years ago

How can I start a new project on solar panels building?

Alborosie

Answer:so you can start by thinking about it and creating ideas that work well with it

Explanation:

Try u can do it

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4 years ago

8.17 Water is the working fluid in a Rankine cycle. Superheated vapor enters the turbine at 10 MPa, 4808C, and the condenser pre

katrin2010 [14]

Answer:

attached below

Explanation:

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3 years ago

Find the Rectangular form of the following phasors?

almond37 [142]

Answer:

The angles are missing in the question.

The angles are :

45, 30, 60, 90, -34, -56, 20, -42, -65, -15

P=10, P=5, P=25, P=54, P=65, P=95, P=250, P=8, P=35, P=150

Explanation:

1. P = 10, θ = 45° rectangular coordinates

x = r cosθ , y = r sinθ

So, rectangular form is x + iy

x = P cosθ = 10 cos 45°

= 7.07

y =P sinθ = 10 sin 45°

= 7.07

Therefore, rectangular form

x + iy = 7.07 + i (7.07)

2. P = 5 , θ = 30°

x = 5 cos 30° = 4.33

y = 5 sin 30° = 2.5

So, (x+iy) = 4.33 + i (2.5)

3. P = 25 , θ = 60°

x = 25 cos 60° = 12.5

y = 25 sin 60° = 21.65

So, (x+iy) = 12.5 + i (21.65)

4. P = 54 , θ = 90°

x = 54 cos 90° = 0

y = 54 sin 90° = 54

So, (x+iy) = 0+ i (54)

5. P = 65 , θ = -34°

x = 65 cos (-34°) = 53.88

y = 65 sin (-34°) = -36.34

So, (x+iy) = 53.88 - i (36.34)

6. P = 95 , θ = -56°

x = 95 cos (-56)° = 53.12

y = 95 sin (-56)° = -78.75

So, (x+iy) = 53.12 - i (78.75)

7. P = 250 , θ = 20°

x = 250 cos 20° = 234.92

y = 250 sin 20° = 85.5

So, (x+iy) = 234.92 + i (85.5)

8. P = 8 , θ = (-42)°

x = 8 cos (-42)° = 5.94

y = 8 sin (-42)° = -5.353

So, (x+iy) = 5.94 - i (5.353)

9. P = 35 , θ = (-65)°

x = 35 cos (-65)° = 14.79

y = 35 sin (-65)° = -31.72

So, (x+iy) = 14.79 - i (31.72)

10. P = 150 , θ = (-15)°

x = 150 cos (-15)° = 144.88

y = 150 sin (-15)° = -38.82

So, (x+iy) = 144.88 - i (38.82)

6 0

3 years ago