-2.5089 kJ is the amount of heat is released by the combustion of the naphthalene.
<h3>How we calculate the released heat?</h3>
Released amount of heat is calculated by using the below formula:
Q = -mcΔT, where
m = mass of naphthalene = 0.25g
c = specific heat of calorimeter = 4.13 kJ/°C
ΔT = change in temperature = 26.43°C - 24°C = 2.43°C
Putting all these values in the above equation, we get
Q = - (0.25 × 4.13 × 2.43) = - 2.5089 kJ
Hence, - 2.5089 kJ heat is released.
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Selective breeding
The Alleles
DNA
X and Y chromosome from mother and father
Nucleus
Gene
<u>Explanation:</u>
- In selective breeding, a specific trait of the animal is considered and the gene coding for that trait is used to create new breeds. Example - cow producing lot of milk.
- Genotypes are always expressed by the alleles.
- Example - Genotype of Tall plants would be TT or Tt
- Information is passed from parents to offsprings from the information stored in DNA.
- A gender of an individual is determined by the x chromosomes of mother and X and Y chromosome of father.
- X chromosome from mother and X chromosome from father would form a female and X chromosome from mother and Y chromosome from father would form a male.
- DNA is located inside the nucleus of the cell
- Gene is the segment of chromosome that codes for a specific protein. The non coding segment of chromososme is heterochromatin.
Given :
0.26 mole of and 0.35 L of water.
To Find :
The molarity of a solution of made by mixing 0.26 mole of potassium
phosphate with water up to 0.35 L .
Solution :
We know, molarity is given by :
Therefore, the molarity of solution is 0.743 M.
Answer:
0.0252mol/L
Explanation:
The following data were obtained obtained from the question:
Volume of solution = 284mL = 284/1000 = 0.284L
Mole of CuSO4 = 7.157 × 10^-3 mol
Molarity =?
Molarity = mole/Volume
Molarity = 7.157x10^-3 /0.284
Molarity = 0.0252mol/L
The concentration of the solution is 0.0252mol/L
The answer is C.
Since KOH and MgCl2 are in a 2:1 ratio, the moles of MgCl2 formed will always be half of the moles of KOH. The only answer where moles of KOH are halved is option C