Answer:
Percent mass of KNO3 in solution = 11% (Approx)
Explanation:
Given:
Mass of KNO3 = 25 grams
Mass of H2O = 200 grams
Find:
Percent mass of KNO3 in solution
Computation:
Mass of solution = 25 + 200 = 225 grams
Percent mass of KNO3 in solution = [25/225]100
Percent mass of KNO3 in solution = 11.111%
Percent mass of KNO3 in solution = 11% (Approx)
Answer:
The answer to your question is T2 = 319.4°K
Explanation:
Data
Volume 1 = V1 = 852 ml
Temperature 1 = T1 = 288°K
Volume 2 = V2 = 945 ml
Temperature 2 = T2 = ?
Process
To solve this problem, use Charles' law.
V1/T1 = V2/T2
-Solve for T2
T2 = V2T1/V1
-Substitution
T2 = (945 x 288) / 852
-Simplification
T2 = 272160 / 852
-Result
T2 = 319.4°K
Answer:
C₄H₁₂ + 7O₂ --> 4CO₂ + 6H₂O
Explanation:
Organic molecules react with O2 to create water and CO2 in combustion processes. C4H12 is an organic molecule that combines with O2 to create water and CO2 as shown in the reactions.
As a result, this is the sole reaction that obeys the general combustion equation.
Astronauts brought back 500 lb of rock samples from the moon. How many kilograms did they bring back? (1 kg = 2.20 lb)
A. 500 kg
B. 1,100 kg
C. 498 kg
D. 227 kg
I believe it is D.
