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3 years ago

Cuantos CM son 8 newtons

Physics

2 answers:

nika2105 [10]3 years ago

6 0

Answer:

uno thos threse u here me

Explanation:

inn [45]3 years ago

4 0

Answer: Be more specific

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Which type of wave is classified as electromagnetic?

Nimfa-mama [501]

Answer: B) Light

Explanation: light waves are Electromagnetic waves. Visible light is one of the many types of electromagnetic waves. The others are mechanical waves.

8 0

3 years ago

Read 2 more answers

The system below uses massless pulleys and ropes. The coefficient of friction is μ. Assume that M1 and M2 are sliding. Gravity i

Archy [21]

Explanation:

Using Newtons second law on each block

F = m*a

Block 1

$T_{1} - u*g*M_{1} = M_{1} *a \\\\T_{1} = M_{1}*(a + u*g) ... Eq1$

Block 2

$T_{2} - u*g*M_{2} = M_{2} *a \\\\T_{2} = M_{2}*(a + u*g) ... Eq2$

Block 3

$- (T_{1} + T_{2} ) + g*M_{3} = M_{3} *a \\\\T_{1} + T_{2} = M_{3}*( -a + g) ... Eq3$

Solving Eq1,2,3 simultaneously

Divide 1 and 2

$\frac{T_{1} }{T_{2}} = \frac{M_{1}*(a+u*g)}{M_{2}*(a+u*g)} \\\\\frac{T_{1} }{T_{2}} = \frac{M_{1} }{M_{2} }\\\\ T_{1} = \frac{M_{1} *T_{2} }{M_{2} } .... Eq4$

Put Eq 4 into Eq3

$T_{2} = \frac{M_{3}*(g-a) }{1+\frac{M_{1} }{M_{2} } } ...Eq5$

Put Eq 5 into Eq2 and solve for a

$a = \frac{M_{3}*g -u*g*(M_{1} + M_{2}) }{M_{1} + M_{2} + M_{3} } .... Eq6$

Substitute back in Eq2 and use Eq4 and solve for T2 & T1

$T_{2} = M_{2}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\T_{1} = M_{1}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\$

5 0

4 years ago

An object attached to a spring is pulled across a horizontal frictionless surface. If the force constant (spring constant) of th

lawyer [7]

Answer:

28.3kg

Explanation:

45=0.88*ml1.4

36.6=0.88m

divide through by 0.88

is said that

m=36.6/0.88

m=28.2857kg

3 0

3 years ago

Which of these attributes is generally attributed to Kepler

kotegsom [21]

Kepler's first "law":
The orbits of the planets are ellipses, with the sun at one focus.
This would include Mars.

3 0

4 years ago

. You have completed your design of a new surgical headlamp. You have decided to power the headlamp using four AA rechargeable b

SSSSS [86.1K]

Answer:

LED run before the batteries are depleted is 3.87 hours

Explanation:

given data

battery = 4 AA

battery is rated = 1.2V, 2550 mAh

power = 3 W

efficient = 95%

to find out

How long will the LED run before the batteries are depleted

solution

we consider here power delivered by battery is = x

so power = x × efficient

3 = x 95%

x = 3.15 W

and

voltage by 4 battery is = 4 × 1.2 = 4.8 V

so current will be = $\frac{x}{volatge}$

current = $\frac{3.15}{4.8}$

current = 0.6577 A

so total discharge hours = $\frac{2550}{current}$

total discharge hours = $\frac{2550}{657.7}$

time = 3.87 hours

so LED run before the batteries are depleted is 3.87 hours

5 0

3 years ago