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3 years ago

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NASA plans to launch a new satellite to orbit the Earth. As the satellite is launched the thrust of the hot exhaust gas is pushe

d through the rocket nozzle and is accelerated toward the rear of the rocket. In turn, the rocket engine is then lifted off of the ground. According to Newton's 3rd law of motion, which statement below is true of the forces involved?
A The downward force exerted by the exhaust on the engine is greater.
B The magnitude of both forces is equal to zero acting in opposite directions.
C Both forces are equal in magnitude, but opposite in direction.
D The upward force exerted by the engine on the exhaust is greater.

2 answers:

kupik [55]3 years ago

8 0

A
Have a great day
Hope this helps

Leya [2.2K]3 years ago

6 0

Answer:

A

Explanation:

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If a home uses a large supply of solar panels to generate electricity, but has no battery system, surplus electricity that is pr

Alinara [238K]

Answer:

Passed into the power grid for others to use the electricity

Explanation:

If a home uses a large supply of solar panels to generate electricity, but has no battery system, surplus electricity that is produced is usually passed into the power grid for others to use the electricity, generating a income to the homeowner

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3. Do you have an issue with the NSA monitoring citizens’ phone calls, text messages, emails, etc.?

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A mass of 1 kg is moving in a circle of radius 3.3 meters. What is the liner velocity v m/s that would give a Centripetal Force

Ghella [55]

Answer:

The linear velocity of the object is 8.71 m/s.

Explanation:

Given;

mass of the object, m = 1 kg

radius of the circle, r = 3.3 meters

centripetal force, F = 23 N

Centripetal force is given by;

$F_c = \frac{mv^2}{r}\\\\$

where;

v is the linear velocity of the object

$F_c = \frac{mv^2}{r}\\\\mv^2 = F_cr\\\\v^2 = \frac{F_cr}{m}\\\\v= \sqrt{\frac{F_cr}{m}} \\\\v= \sqrt{\frac{23*3.3}{1}}\\\\v = 8.71 \ m/s$

Therefore, the linear velocity of the object is 8.71 m/s.

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3 years ago

An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char

ArbitrLikvidat [17]

Answer:

Part a)

$W = 1.58 \times 10^{-20} J$

Part b)

$v = 1.86 \times 10^5 m/s$

Explanation:

Part a)

Electric field due to large sheet is given as

$E = \frac{\sigma}{2\epsilon_0}$

$\sigma = 4.00 \times 10^{-12} C/m^2$

now the electric field is given as

$E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}$

$E = 0.225 N/C$

Now acceleration of an electron due to this electric field is given as

$a = \frac{eE}{m}$

$a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}$

$a = 3.97 \times 10^{10}$

Now work done on the electron due to this electric field

$W = F.d$

$d = 0.470 - 0.03$

$d = 0.44 m$

So work done is given as

$W = (ma)(0.44)$

$W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)$

$W = 1.58 \times 10^{-20} J$

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

$W = \frac{1}{2}mv^2 - 0$

$1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2$

$v = 1.86 \times 10^5 m/s$

7 0

3 years ago

A planar electromagnetic wave is propagating in the +x direction. At a certain point P and at a given instant, the electric fiel

jeka94

Answer:

$B=2.74\times 10^{-10}\ T$

Explanation:

It is given that,

A planar electromagnetic wave is propagating in the +x direction.The electric field at a certain point is, E = 0.082 V/m

We need to find the magnetic vector of the wave at the point P at that instant.

The relation between electric field and magnetic field is given by :

$c=\dfrac{E}{B}$

c is speed of light

B is magnetic field

$B=\dfrac{E}{c}\\\\B=\dfrac{0.082}{3\times 10^8}\\\\B=2.74\times 10^{-10}\ T$

So, the magnetic vector at point P at that instant is $2.74\times 10^{-10}\ T$ .

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3 years ago