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Vedmedyk [2.9K]
3 years ago
15

What is the length of a one-dimensional box in which an electron in the n=1 state has the same energy as a photon with a wavelen

gth of 800 nm ?
Physics
1 answer:
Pie3 years ago
3 0

Answer:

Length will be 0.491 nm

Explanation:

We have given wavelength of the photon \lambda =800nm=800\times 10^{-9}m

Plank's constant h=6.6\times 10^{-34}J-s

We know that energy of the photon is given by

E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{800\times \times 10^{-9}}=2.475\times 10^{-19}J

We know that energy of photon is also given by

E=\frac{n^2h^2}{8mL^2}=\frac{h^2}{8mL^2}

2.475\times 10^{-19}=\frac{(6.6\times 10^{-34})^2}{8\times 9.1\times 10^{-31}\times L^2}

L=0.491\times 10^{-9}m

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Two planets have masses 2 x 10^23 kg and 5 x 10^22 kg, and the distance between them is 3 x 10^16 m. Calculate the gravitational
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Explanation:

given,

mass of one planet (m1)=2*10^23 kg

mass of another planet (m2)=5*10^22kg

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gravitational force between them(F)=?

we know,

F=Gm1m2/d^2

or, F=6.67*10^-11*2*10^23*5*10^22/(3*10^16)^2

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3 years ago
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Explanation:

7 0
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A race car traveling at 10 meters per second accelerates at 1.5 meters per second squared while moving a distance of 600 meters.
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Answer:

Explanation:

Givens

vi = 10 m/s

a = 1.5 m/s^2

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vf = ?

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vf^2 = vi^2 + 2*a*d

Solution

vf^2 = 10^2 + 2*1.5 * 600

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vf^2 = 1900

sqrt(vf^2) = sqrt(1900)

vf = 43.59 m/s

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