Ask question

Ask question

All categories

2 years ago

6

Can someone Help pls :)

1 answer:

s344n2d4d5 [400]2 years ago

5 0

Answer:

D. I think

Explanation:

You might be interested in

Fluorine (F) and bromine (Br) are in the same group on the periodic table. How do atoms of these elements compare when they form

stiks02 [169]

Answer:

they both gain one electron

Explanation:

they are both halogens and they each have one unpaired electron so that unpaired electron join together to make them form a bond

5 0

3 years ago

The __lithosphere__ combines the two crusts, oceanic and continental, with the coolest part of the __________________. The asthe

zmey [24]

Answer:

The lithosphere And the upper mantle combines the two crusts, oceanic and continental, with the coolest part of the Crust?. The asthenosphere allows the tectonic plates to slide on the putty substance of the mantle and the mesosphere is the Smallest? part of the mantle. The outer core is hot enough to turn the metal into a Liquid The inner core is the hottest but the extreme pressure makes it a Solid.

8 0

2 years ago

Read 2 more answers

What is the overall cell potential for this redox reaction? Ca2+ + 2Li = Ca + 2Li+ Ca2+ + 2e- = Ca -2.87 V Li = Li+ + e- -3.05 V

Jet001 [13]

The redox reaction is

$Ca^{+2} + 2Li(s) = Ca(s) + 2Li^{+}$

Here

Calcium undergoes reduction, and acts as cathode

Lithium undergoes oxidation and acts as anode

The reduction potential of calcium is -2.87 V

The reduction potential of lithium is - -3.05 V

We know that

Ecell = Ecathode - Eanode

Ecell = -2.87 - (-3.05) = 0.18 V

4 0

3 years ago

A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

sergey [27]

Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

$v_1$ = 200 ml

$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

$v_2=\frac{276}{299} \times 200 = 184.62 \; ml$

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

7 0

2 years ago

) In another experiment, the student titrated 50.0mL of 0.100MHC2H3O2 with 0.100MNaOH(aq) . Calculate the pH of the solution at

andrew11 [14]

Answer:

Explanation:

moles of acetic acid = 500 x 10⁻³ x .1 M

= 5 X 10⁻³ M

.005 M

Moles of NaOH = .1 M

Moles of sodium acetate formed = .005 M

Moles of NaOH left = .095 M

pOH = 4.8 + log .005 / .095

= 4.8 -1.27875

= 3.52125

pH = 14 - 3.52125

= 10.48

6 0

2 years ago