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Ray Of Light [21]
3 years ago
12

Noble gases are unreactive because of their electronic structures. The kind of reasoning that states "if other elements could be

made to achieve noble gas electronic structures they would be more stable" is called ________.
a) logic
b) inductive reasoning
c) deductive reasoning
d) critical thinking
Chemistry
1 answer:
Goshia [24]3 years ago
8 0

Answer:

C. Deductive reasoning

Explanation:

Deductive reasoning is a reasoning or logical process whereby a conclusion is drawn based on the belief of multiple premises that are generally assumed to be true. It is a logical process in which one or multiple statements reaches a logical conclusion.

In the question, the statement assumed to be true is that <em>noble gases are unreactive because of their electronic structures.</em>

The conclusion thus drawn from the premise is that <em>if other elements could be made to achieve noble gases electronic structures (</em><u><em>this is the reason why they are unreactive - the fact)</em></u><em> they would be more stable.</em>

<em />

Therefore, deductive reasoning moves from a wilder reasoning to a specific (narrower) reasoning.

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Q3. A bridge is built without expansion gaps.
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Answer:

Q3. A bridge is built without expansion gaps.

Explain what could happen to the bridge if the temperature became:

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Arizona was the site of a 400,000-acre wildfire in June 2002. How much carbon dioxide (CO2) was produced into the atmosphere by
kodGreya [7K]

Answer:

2.97 × 10¹³ g

Explanation:

First, we have to calculate the biomass the is burned. We can establish the following relations:

  • 2.47 acre = 10,000 m²
  • 10 kg of C occupy an area of 1 m²
  • 50% of the biomass is burned

The biomass burned in the site of 400,000 acre is:

400,000acre\times\frac{10,000m^{2} }{2.47acre} \times \frac{10kgC}{m^{2} } \times 50\% = 8.10 \times 10^{9} kgC

Let's consider the combustion of carbon.

C(s) + O₂(g) ⇒ CO₂(g)

We can establish the following relations:

  • The molar mass of C is 12.01 g/mol
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The mass of  produced is CO₂:

8.10 \times 10^{12}gC \times \frac{1molC}{12.01gC} \times \frac{1molCO_{2}}{1molC} \times \frac{44.01gCO_{2}}{1molCO_{2}} =2.97 \times 10^{13} gCO_{2}

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