Explanation:
A low-pressure area, or "low", is a region where the atmospheric pressure at sea level is below that of surrounding locations. Low-pressure systems form under areas of wind divergence that occur in upper levels of the troposphere.
Let's see. It's definitely not the O horizon, because that layer is at the very top. A is already eliminated. Same thing with the A horizon, that is actually the top soil. C is out. It has to be either B or D. A D layer doesn't exist, so B is out. But the B horizon is considered a region of subsoil. The answer is D: B horizon.
<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %
<u>Explanation:</u>
The given chemical formula of lead (IV) carbonate is
To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:
Mass of lead = (1 × 207.2) = 207.2 g
Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g
Putting values in above equation, we get:
Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %
Explanation:
Oxidizing agent is the reactant in the chemical reaction which oxidizes others and reduces itself.
Reducing agent is the reactant in the chemical reaction which reduces others and oxidizes itself.
(a) In the given reaction :-
Cr exists in +6 oxidation state in and forms in which it has +3 oxidation state.
Thus, it is reduced in the chemical reaction. Thus, is oxidizing agent and is the reducing agent.
(b) In the given reaction :-
Zn exists in 0 oxidation state in and forms in which it has +2 oxidation state.
Thus, it is oxidized in the chemical reaction. Thus, Zn is reducing agent and is the oxidizing agent.
I believe the answer to this question is true