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Gwar [14]
4 years ago
10

The unique name given to each organism ; made up of Genus and species..is..?

Physics
1 answer:
True [87]4 years ago
6 0
A binomial nomenclature, more commonly referred to as a scientific name.
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Because each earthquake can go in different places which the wind moves different and then the earth moves different.
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Which of one example of pre-existing marine life?
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B. a shrimp burrow cause A,C,D is above the sea/ocean
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An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.210 rev/s. The magnitude
damaskus [11]

Answer:

Explanation:

Given that

Initial velocity wo=0.210rev/s

Then, 1rev=2πrad

wo=0.21×2πrad/s

wo=0.42π rad/s

Given angular acceleration of 0.9rev/s²

α=0.9×2πrad/s²

α=1.8π rad/s²

Diameter of blade

d=0.75m,

Radius=diameter/2

r=0.75/2=0.375m

a. Angular velocity after t=0.194s

Using equation of angular motion

wf=wo+αt

wf=0.42π+ 1.8π×0.194

wf= 0.42π + 0.3492π

wf=1.319+1.097

wf= 2.42rad/s

If we want the answer in revolution

1rev=2πrad

wf= 2.42/2π rev/s

wf=0.385 rev/s

b. Revolution traveled in 0.194s

Using angular motion equation

θf - θi = wo•t + ½ αt²

θf - 0= 0.42π•0.194 + ½ × 1.8π•0.194²

θf = 0.256 + 0.106

θf = 0.362rad

Now, to revolution

1rev=2πrad

θf=0.362/2π=0.0577rev

Approximately θf= 0.058rev

c. Tangential speed? At time 0.194s

Vt=?

w=2.42rad/s at t=0.194s

Using circular motion formulae, relationship between linear velocity and angular velocity

V=wr

Vt=wr

Vt= 2.42×0.375

Vt=0.9075 m/s

Vt≈0.91m/s

d. Magnitude of resultant acceleration

Tangential Acceleration is given as

at=αr

at=1.8π× 0.375

at=2.12rad/s²

Now, radial acceleration is given as

ar=w²r

ar=2.42²×0.375

ar=2.196 m/s²

Then, the magnitude is

a=√ar²+at²

a=√2.196²+2.12²

a=√9.3171

a=3.052m/s²

a≈ 3.05m/s²

8 0
3 years ago
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Match each Sun-Earth-Moon alignment diagram to the corresponding eclipse image, as seen from Earth.
zvonat [6]

Answer:

Explanation:

Here ya go

I've also corrected the moon position relative to the penumbra. It's much more representative to the actual geometry but still not very accurate because of the vast distances between moon, earth and sun. Could not do much with the quarter moon with realism because of scales.

5 0
3 years ago
A wheel with rotational inertia 0.04 kg•m2 and radius 0.02 m is turning at the rate of 10 revolutions per second when a friction
Rus_ich [418]

Answer:

-78.96 J

Explanation:

The workdone by the torque in stopping the wheel = rotational kinetic energy change of wheel.

So W = 1/2I(ω₁² - ω₀²) where I = rotational inertia of wheel = 0.04 kgm², r = radius of wheel = 0.02 m, ω₀ = initial rotational speed = 10 rev/s × 2π = 62.83 rad/s, ω₁ = final rotational speed = 0 rad/s (since the wheel stops)

W = 1/2I(ω₁² - ω₀²) = 1/2 0.04 kgm² (0² - (62.83 rad/s)²) = -78.96 J  

7 0
4 years ago
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