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3 years ago

Five 6 ohm resistors are connected in parallel. Which of the following is their effective resistance?

Physics

1 answer:

Ganezh [65]3 years ago

3 0

1/Rt = 1/R1 + 1/R2 + 1/R3+ 1/R4+ 1/R5

1/Rt = 1/6+ 1/6+1/6+1/6+1/6

1/Rt = 5/6

Rt = 6/5

Rt = 1.2 ohm

so B is the answer

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A student walks the hallway for 25 m stops to talk and continues down the hallway another 10 m what is the distance and displace

brilliants [131]

Answer:

Distance = displacement = 35m

Explanation:

The distance of the student is how far he has gone.

Distance = 25m + 10m

Distance = 35m

Displacement is the distance specified in specific direction. Since the student walk in the sane direction, thence the displacement is also 35m

3 0

3 years ago

A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begin

lyudmila [28]

Part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
$W= \int\limits^{0.540m}_{0} {F} \, dx = \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx =$
$=16000x+10000 \frac{x^2}{2} - 26000 \frac{x^3}{3}$
By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
$W=16000(0.540m)+10000 \frac{(0.540m)^2}{2} - 26000 \frac{(0.540m)^3}{3} =$
$=8733 J=8.73 kJ$

part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
$W=16000(0.95m)+10000 \frac{(0.95m)^2}{2} - 26000 \frac{(0.95m)^3}{3} =$
$=12280 J=12.28 kJ$

5 0

2 years ago

What is a small body that follows a highly elliptical orbit around the sun

melomori [17]

A Planet, such as (pluto)

4 0

3 years ago

Read 2 more answers

A 800 kg safe is 2.1 m above a heavy-duty spring when the rope holding the safe breaks. The safe hits the spring and compresses

stellarik [79]

Answer:

k = 17043.5 N/m = 17.04 KN/m

Explanation:

First we need to find the force applied by safe pn the spring:

F = Weight of Safe

F = mg

where,

F = Force Applied by the safe on the spring = ?

m = mass of safe = 800 kg

g = 9.8 m/s²

Therefore,

F = (800 kg)(9.8 m/s²)

F = 7840 N

Now, using Hooke's Law:

F = kΔx

where,

K = Spring Constant = ?

Δx = compression = 46 cm = 0.46 m

Therefore,

7840 N = k (0.46 m)

k = 7840 N/0.46 m

k = 17043.5 N/m = 17.04 KN/m

5 0

3 years ago

Henry was giving the school toy for his birthday he can use it to tell how fast someone is moving at the moment in time the toy

pochemuha

Answer:

The toy must calculate the person's speed/velocity

Explanation:

Since the school toy given to Henry can be used to tell how fast someone is moving, the toy must be able to calculate the person's speed/velocity using the average distance covered by the person divided by time taken to cover the distance; average distance ÷ time taken.

The toy must be able to determine the parameters (average distance and time taken) in order to be able to calculate the person's speed/velocity

5 0

2 years ago