A 300 kg box rests on a platform attached to a forklift shown. Starting from rest at time t = 0 seconds, the box is lowered with
1 answer:
Answer:
N = 2490 N
Explanation:
Determine the upward force exerted by the horizontal platform on the box as it is lowered.
It is given that,
Mass of a box, m = 300 kg
Starting from rest at time t = 0 seconds, the box is lowered with a downward acceleration of 1.5 m/s².
It is assumed to find the upward force exerted by the horizontal platform on the box. It is given by :
mg-N=ma
So, the normal force is 2490 N.
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Answer:
0.3858 Nm
Explanation:
The torque of the couple is the dot product of the force vector and the couple vector from 1 end of the ruler to the center. This equals to the product of their magnitude times the cosine() of the angle made by their direction:
To solve this problem we will apply the concepts related to the Doppler effect. According to this concept, it is understood as the increase or decrease of the frequency of a sound wave when the source that produces it and the person who captures it move away from each other or approach each other. Mathematically this can be described as
Here,
= Original frequency
= Velocity of the observer
= Velocity of the speed
Our values are,
Using the previous equation,
Rearrange to find the velocity of the observer
Replacing we have that
Therefore the velocity of the observer is 16.2m/s