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attashe74 [19]
3 years ago
5

A moving car has momentum. if it moves twice as fast its momentum is ____________ as much

Physics
1 answer:
Nikolay [14]3 years ago
3 0
It's momentum is twice as much.
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How much work is done by the force lifting a
Ann [662]

The work done in lifting the hamburger is equal to the increase in gravitational potential energy of the hamburger, given by

W=\Delta U=mg \Delta h

where

m=0.1 kg is the mass of the hamburger

g=9.81 m/s^2 is the gravitational acceleration

\Delta h=0.3 m is the increase in height of the hamburger


Substituting numbers into the equation, we find

W=(0.1 kg)(9.81 m/s^2)(0.3 m)=0.3 J


So, the correct answer is

(3) 0.3 J

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Seesaw unbalanced force explain
wolverine [178]
Like a seesaw, it shows that the forces aren’t equal because if it was the seesaw would stay put
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2 years ago
Does the mass of a pendulum affects the period of oscillation
pshichka [43]
Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.
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The acceleration of a train moving from rest and its speed reaches 36m/sec in 9 sec​
jenyasd209 [6]

Answer:

4 m/s^2

Explanation:

The acceleration is defined as: Δv/Δt (the difference of the velocity over a time period in which happens that difference).

Remember that a difference is calculated by subtracting the initial value of a physical quantity from its final value.

In our case:

Δv = Vfinal - Vinitial = 36m/s - 0 m/s = 36m/s

Δt = 9s

a = Δv/Δt = 36m/s / 9s = 4m/s^2

4 0
2 years ago
A body has masses of 0.013kg and 0.012kg in oil and water respectively, if the relative density of oil is 0.875, calculate the m
konstantin123 [22]

Answer:

the mass of the body is 0.02 kg.

Explanation:

Given;

relative density of the oil, \gamma _0 = 0.875

mass of the object in oil, M_o = 0.013 kg

mass of the object in water, M_w = 0.012 kg

let the mass of the object in air = M_a

weight of the oil, W_0 = M_a - 0.013

weight of the water, W_w = M_a - 0.012

The relative density of the oil is given as;

\gamma_0 = \frac{density \ of \ oil }{density \ of \ water} = \frac{W_0}{W_w} = \frac{M_a -0.013}{M_a -0.012} \\\\0.875 = \frac{M_a -0.013}{M_a -0.012}\\\\0.875(M_a - 0.012) = M_a - 0.013\\\\0.875M_a - 0.0105 = M_a -0.013\\\\0.875M_a - M_a = 0.0105 - 0.013\\\\-0.125 M_a = -0.0025\\\\M_a = \frac{0.0025}{0.125} \\\\M_a = 0.02 \ kg

Therefore, the mass of the body is 0.02 kg.

6 0
2 years ago
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