Explanation:
because there are 4 Iodines on the left, we'll put. 4 in front of NaI to balance it. This would result in 4 Na on the left, so we'll put a 2 in front of Sodium Sulfate to balance the right side. Now we have 4 Na and I on both side, as well as 2 Sulfate on both sides. Pb is already balanced. The equation is now complete.
Answer:
6.73g
Explanation:
T½ = 5.2days
No = 80g
N = ?
T = 20.8days
We'll have to find the disintegration constant first so that we can plug it into the equation that will help us find the mass of the sample after 20.8 days
T½ = In2 / λ
T½ = half life
λ = disintegration constant
λ = In2 / T½
λ = 0.693 / 5.8
λ = 0.119
In(N / No) = -λt
N = final mass of the radioactive sample
No = initial mass of the sample
λ = disintegration constant
t = time for the radioactive decay
In(N/No) = -λt
N / No = e^-λt
N = No(e^-λt)
N = 80 × e^-(0.119 × 20.8)
N = 80 × e^-2.4752
N = 80 × 0.0841
N = 6.728g
The mass of the sample after 20.8 days is approximately 6.73g
Answer:
Yes, acetic acid could be used, but it would not be as effective as acetyl chloride or acetic anhydride. ... However, the acetic anhydride would still be reacting with an alcohol, so nothing changes in that respect. Also, the reaction would need to be done in basic solution.
The grams of FeO that would be needed to make 234.2 grams of Fe is
1204.42 grams
<u><em> calculation</em></u>
4 FeO → Fe₃O₄ +Fe
Step 1: find the moles of fe
moles = mass /molar mass
from periodic table the molar mass of Fe = 56 g/mol
moles = 234.2 g/56 g/mol = 4.182 moles
Step 2: use the mole ratio to determine the moles of FeO
FeO: Fe is 4:1 therefore the moles of FeO =4.182 moles x4 =16.728 moles
Step 3: find the mass of FeO
mass = moles x molar mass
The molar mass of FeO = 56 +16 = 72 g /mol
mass = 16.728 moles x 72 g/mol= 1204.42 grams