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Nat2105 [25]
2 years ago
7

The given reaction is second order with respect to A, first order with respect to B and zero order with

Chemistry
1 answer:
Rzqust [24]2 years ago
5 0

All reactants concentration are tripled

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Calculate the silver ion concentration in a saturated solution of silver(i) sulfate (ksp = 1.4 × 10–5).
deff fn [24]

Answer:

= 0.030 M

Explanation:

We can take x to be the concentration in mol/L of Ag2SO4 that dissolves  

Therefore;  concentration of  Ag+ is 2x mol/L and that of SO4^2- x mol/L.

Ksp = 1.4 x 10^-5

Ksp = [Ag+]^2 [SO42-]

      = (2x)^2(x)

      = 4x^3  

Thus;

4x^3  = 1.4 x 10^-5

         = 0.015 M

molar solubility = 0.015 M

But;

[Ag+]= 2x

Hence; silver ion concentration is

= 2 x 0.015 M

= 0.030 M

6 0
3 years ago
The number of nucleons of an isotope represents the total number of..
Elza [17]

Answer:

The mass number (A), also called atomic mass number or nucleon number, is the total number of protons and neutrons (together known as nucleons) in an atomic nucleus. The mass number is different for each different isotope of a chemical element.

3 0
2 years ago
Select the correct answer.
Nitella [24]

Answer:

C.

Explanation:

Iron is most likely to form a precipitation reaction.

8 0
3 years ago
Is the mass of .00566 mol of germanium (Ge) greater than one gram or less<br> than one gram?
Salsk061 [2.6K]

Answer:

Less than one gram

Explanation:

Since there is no whole number before the decimal it means that the number is less than whole meaning it is less than one gram

8 0
2 years ago
A student weighs an empty flask and stopper and finds the mass to be 53.256 g. She then adds about 5 mL of an unknown liquid and
Delvig [45]

Answer:

a. The pressure in the flask open to the atmosphere during the vaporization of the unknown liquid is equal to the prevailing atmospheric pressure equivalent to 0.957734 atm

Explanation:

The mass of the empty flask and stopper, m = 53.256 g

The volume of the unknown liquid she adds = 5 mL

The temperature of the water in which she heats up the flask = 98.8 °C = 371.95 K

The mass of the flask and the condensed vapor = 53.780 g

The volume of the flask, V = 231.1 mL

The atmospheric pressure, P = 728 mm Hg

a. We note that the student stoppers the flask after all the liquid has evaporated. Therefore, given that the flask was open to the atmospheric pressure as the liquid evaporates, the pressure of the vapor in the flask is equal to the prevailing atmospheric pressure, or 728 mmHg

Using a calculator, 728 mm Hg is equivalent to 0.957734 atm.

3 0
3 years ago
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