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3 years ago

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Camille has a stamp collection she is very proud of. She buys a frame to display her favorite stamps. The frame is 6 inches wide

, and a row of 7 stamps fits perfectly across it. How wide is each stamp?

1 answer:

Zielflug [23.3K]3 years ago

4 0

Answer:

6 ÷ 7 inches

Step-by-step explanation:

The computation of the width of each stamp is shown below;

Given that

The frame is 6 inches wide

And, the row is 7 stamp fits perfectly across it

So, the width of each stamp is

= 6 ÷ 7 inches

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liubo4ka [24]

Answer:

0.93

Step-by-step explanation:

u have to add them all and divide by 12. then u add all of them but the outlier and divide by 11. then u subtract.

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3 years ago

4x10^4 in standard notation

lyudmila [28]

Answer:

40000

Step-by-step explanation:

4×10^4 = 4×10000 = 40000

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3 years ago

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Select True or false for each statement

PilotLPTM [1.2K]

Answer:

False

True

False

False

Step-by-step explanation:

1. We have to get the sum as follows :

$3\frac{4}{9} + 4\frac{6}{9}$

= $\frac{31}{9} + \frac{42}{9}$

= $\frac{31 + 42}{9}$

= $\frac{73}{9}$

= $8\frac{1}{9} \neq 7\frac{1}{9}$

So, this is false.

2. We have to get the sum as follows :

$4\frac{5}{6} + 1\frac{3}{6}$

= $\frac{29}{6} + \frac{9}{6}$

= $\frac{29 + 9}{6}$

= $\frac{38}{6}$

= $6\frac{2}{6}$

So, this is true.

3. We have to get the difference as follows :

$4\frac{5}{8} - 2\frac{4}{8}$

= $\frac{37}{8} - \frac{20}{8}$

= $\frac{37 - 20}{8}$

= $\frac{17}{8}$

= $2\frac{1}{8} \neq 2\frac{3}{8}$

So, this is false.

4. We have to get the difference as follows :

$7\frac{5}{8} - 4\frac{2}{8}$

= $\frac{61}{8} - \frac{34}{8}$

= $\frac{61 - 34}{8}$

= $\frac{27}{8}$

= $3\frac{3}{8} \neq 3$

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3 years ago

How many different phone numbers are possible in the area code 503, if the first number cannot start with a 0 or 1

ElenaW [278]

Answer:

8 X 10^(9)

Step-by-step explanation:

Originally we have 10 digit phone numbers excluding the area code.

For each face value we have these in store: 0,1,2,3,4,5,6,7,8,9 (total 10)

But if we exclude 1 and 0 for the first digit, we are left with 8 digits.

8P1 X .......

In a phone number, digits can repeat so we can choose out of these 10 numbers freely after this.

8P1 X 10P1 X 10P1 X...

Adding the area code while assuming 10P1 is just 10...we get:

1 X 1 X 1 X 8 X 10^(9)

= 8000000000

Very interesting question, thanks for the opportunity!

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3 years ago

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Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born

NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of a person being in May:

May has 31 days in a year of 365. So

$p = \frac{31}{365} = 0.0849$

Group of 20 friends:

This means that $n = 20$

What is the probability that at the May celebration, exactly two members of the group have May birthdays?

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{20,2}.(0.0849)^{2}.(0.9151)^{18} = 0.2773$

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

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3 years ago