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Serhud [2]
3 years ago
11

" alt="V = \frac{4}{3} \pi .r3" align="absmiddle" class="latex-formula">
Physics
1 answer:
pogonyaev3 years ago
6 0
The formula is the volume of a *sphere* ... l hope it helped:)
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In Trial III, a different, looser, spring is used; its force constant is 23.1 N/m. The suspended mass is the same as the one in
cricket20 [7]

Answer:

T=0.827s

Explanation:

The period of a spring can be calculated with the equation

T=2\pi w

But we know as well that w is given by,

w=\sqrt{\frac{k}{m}}

Replacing,

w=\frac{2\pi}{T}= \sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{k}{m}}\\T=2\pi\sqrt{\frac{0.4}{23.1}}

So we have that

T=0.827s

7 0
3 years ago
The abbreviation ucs stands for
LenaWriter [7]
It stands for Unified Computing System

I hope I helped :3
3 0
4 years ago
Read 2 more answers
Why is it not possible to achieve a higher resolution in the light microscope?.
Rudiy27

Higher resolution cannot be achieved with a light microscope because wavelength of light is larger that wavelength of electrons.

<h3>What is light microscope?</h3>

Light microscope is defined as the type of microscope that makes use of visible light to magnify objects into images that can be observed.

The wavelength of light is larger than that of the electrons, therefore, higher resolution cannot be achieved with a light microscope.

Learn more about microscope here:

brainly.com/question/15744335

#SPJ1

3 0
2 years ago
Calculate the kinetic energy of a 2.2kg brick when it has a speed of 4.9m/s
Alborosie

Answer:

Kinetic energy of the brick is 26.4 Joule

3 0
3 years ago
Read 2 more answers
What net force is required to accelerate a car at a rate of 2m/s^2 if the car has a mass of 3,000kg? plus explanation with equat
Vinvika [58]

Answer:

<h2>6000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 3000 kg

acceleration = 2 m/s²

We have

force = 3000 × 2 = 6000

We have the final answer as

<h3>6000 N</h3>

Hope this helps you

3 0
2 years ago
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