1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SCORPION-xisa [38]
3 years ago
9

group of students is making model cars that will be propelled by model rocket engines. These engines provide a nearly constant t

hrust force. The cars are light—most of the weight comes from the rocket engine—and friction and drag are very small. As the engine fires, it uses fuel, so it is much lighter at the end of the run than at the start. A student ignites the engine in a car, and the car accelerates. As the fuel burns and the car continues to speed up, the magnitude of the acceleration will
Physics
1 answer:
iris [78.8K]3 years ago
7 0

Answer:

increase.

Explanation:

According to the newton’s second law of motion force is expressed as product of mass and acceleration.

F = m a

If the force acting is constant, then.

m∝ \frac{1}{a}

That is if the mass of object increases the acceleration decreases and vice versa. The above equation is used when the force acting on the body is constant.

As the thrust force from the rocket engine is constant throughout there will be a variation in the mass or acceleration.

Thus, it won't stay the same.

As the weight of the car is maximum at the start because of the fuel present in the rocket engine and minimum at the end as the fuel burns throughout the journey of the car. Weight will be minimum at the end and hence acceleration is maximum at the end.

Thus, it won't decrease.

As the acceleration is going from minimum at the start to maximum at the end, therefore it is continuously increases throughout its journey.

Thus, it will increase.  

You might be interested in
What is 9414 divided by 18​
Levart [38]
9414/18 is equal to 523
3 0
3 years ago
Two identical resistors connected in series have an equivalent resistance of 4 ohms. The same two resistors, when connected in p
irina1246 [14]

Answer:

1 ohm

Explanation:

since there are two identical resistors, one resistor will be

R = \frac{4}{2} =2ohm [ proven as in series R_{e} = 2 + 2 = 4ohm ]

to calculate the equivalent resistance when in parallel:

\frac{1}{R_{e} }  = \frac{1}{R_{1} } + \frac{1}{R_{2}}

so,

\frac{1}{R_{e} } = \frac{1}{2} + \frac{1}{2}

R_{e} = 1ohm

4 0
3 years ago
What is the weight of a 4.2 kg bowling ball on Mars?
Nataliya [291]

What is the weight of a 4.2 kg bowling ball on Mars?

Answer:

1.59 kg

Explanation:

The formula is:

<u>F = G((Mm)/r2) </u>

F is the gravitational force between two objects,

G is the Gravitational Constant (6.674×10-11 Newtons x meters2 / kilograms2),

M is the planet's mass (kg),

m is your mass (kg), and

r is the distance (m) between the centers of the two masses (the planet's radius).

Hope this helps

--Jay

8 0
3 years ago
A rubber ball is dropped from a height of 8m. After strikingthe floor, the ball bounces to a height of 5m. a. If the ball had bo
kifflom [539]

Answer:

a) This means the collision between the ball and the floor is elastic.

b) This points to a perfectly inelastic collision between the ball and the floor as they stick together after collision

c) Check Explanation.

Explanation:

Collision of bodies are analysed according to whether both momentum and kinetic energy of the system is conserved, that is, if these two quantities before collision are equal to their values after collision.

In all types of collisions, momentum is usually conserved, but kinetic energy is conserved only in an elastic collision.

A ball dropped from a height of 8 m bounces up back to a height of 5 m.

a. If the ball had bounced to a height of 8m, how would you describe the collision between the ball and the floor?

The ball not bouncing back to a height of 8 m shows energy loss at some point in the total motion of the ball (most likely at the collision). If kinetic energy was conserved, the ball would bounce back up to the height at which it fell from (8 m) after the collision with the floor.

b. If the ball had not bounced at all, how would you describe the collision between the ball and the floor?

If the ball had not bounced at all, this means it lost all of its kinetic energy to the floor, and this points to a perfectly inelastic collision between the ball and the floor as they stick together after collision.

c. What happened to the energy lost by the ball during thecollision?

The energy lost during the collision is converted to another form, most likely responsible for some deformation on the ball & a minute deformation on the floor, converted to some form of heat as a result of the collision or into sound energy, usually, it's a combination of all This!

Hope this Helps!!!

5 0
3 years ago
If a force of 26 N is applied to an object with a mass of 8 kg, the object will accelerate at m/s2
malfutka [58]
False, the numbers do not add up
8 0
3 years ago
Read 2 more answers
Other questions:
  • A car traveling with constant speed travels 150 km in 7200 s. What is the speed of the car?
    15·2 answers
  • Help with everything
    9·1 answer
  • What was the speed of a space shuttle that orbited Earth at an altitude of 1482 km?
    6·2 answers
  • Patients with brain tumors may elect to have a procedure known as Gamma Knife. In a typical Gamma Knife procedure gamma rays are
    9·2 answers
  • A ball rolls for 8 seconds and travels 24 meters. How fast was it traveling?
    9·1 answer
  • PLSEAE HELP ME I WILL GIVE BRIANLYEST!!!!
    5·1 answer
  • Premium
    7·2 answers
  • A rock stays in the same position without moving, which law is it ?
    8·1 answer
  • please help me with my question I will like and mark as brainliest for the first correct answer due tomorrow morning​
    10·1 answer
  • Zach, whose mass is 85 kg, is in an elevator descending at 8 m/s. The elevator takes 3.2 s to brake to a stop at the first floor
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!