X=bt + ct3, b=1.50m/s, c=0.640m/s3.
Average velocity = distance / time
ti = 1.00, tf = 3.00
xi = (1.50)(1.00) + (0.640 )(1.00)^3 = 1.5 + 0.640 = 2.14 m
xf = = (1.50)(3.00) + (0.640)(3.00)^3 = 4.5 + 27(17.28) = 21.78 m
Ave Velocity = (21.78 - 2.14) / (3 - 1) = 9.82 m/s
They can be described as small in quantity and very dangerously radioactive.
Answer:
The spring constant is
Explanation:
Given that,
length = 500 mm
Diameter = 2 cm
Young's modulus = 17.4 GPa
We need to calculate the young's modulus
Using formula of young's modulus
....(I)
From hook's law
....(II)
Put the value of F in equation
We need to calculate the spring constant
....(II)
We need to calculate the area of cylinder
Using formula of area of cylinder
Put the value into the formula
Put the value of A in (II)
Hence, The spring constant is
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