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oksian1 [2.3K]
3 years ago
5

What is the difference between work input and work output

Physics
1 answer:
FromTheMoon [43]3 years ago
6 0
Work input is something done with a simple machine.
Output is the same except the use more compound machines with less force.
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List the color of the stars from hottest to coldest
masha68 [24]
Blue, blue-white, Yellow-white, yellow, yellow-orange, and red. Hope this helps.
8 0
3 years ago
a 10 kg block is attached to a light chord that is wrapped around the pulley of an electric motor. at what rate is the motor doi
defon

Answer:

The rate of work is 360 W

Explanation:

Given:

Speed of block v = 3 \frac{m}{s}

Upward acceleration of block a = 2 \frac{m}{s^{2} }

Mass of block m = 10 kg

First Find the force act on block due to gravity

  F = M (a + g)

Where g = 10 \frac{m}{s^{2} }

  F = 10 \times (10+2)

  F = 120 N

For finding at what rate motor doing work when it is pulling the block upward,

  P = F.v

  P = 120 \times 3

  P = 360 W

Therefore, the rate of work is 360 W

6 0
3 years ago
During a single-replacement reaction, a more-active metal will replace a less-active metal in a compound. Which single-replaceme
son4ous [18]

Answer:

Mg will replace Ag in a compound

Explanation:

A single replacement reaction is driven by the position of ions on the activity series.

As a rule of thumb, the position of metal ions on the activity series determines their reactivity.

Metal ions that are above another are more reactive and they will displace those that are lower.

Generally, activity increases as we go up the group.

Mg ions are higher than Ag ions on the series so, Mg will displace Ag from a solution.

8 0
3 years ago
Many types of decorative lights are connected in parallel. If a set of lights is connected to a 110 V source and the filament of
Oksi-84 [34.3K]

Answer:

i₀ = V / R_i

Explanation:

For this exercise we use Ohm's law

         V = i R

          i = V / R

the equivalent resistance for

         \frac{1}{R_{eq}} =  ∑ \frac{1}{R_i}

if all the bulbs have the same resistance, there are N bulbs

         \frac{1}{ R_{eq}} = \frac{N}{R_i}

         R_{eq} = R_i / N

we substitute

         i = N V / Ri

where i is the total current that passes through the parallel, the current in a branch is

         i₀ = i / N

         i₀ = V / R_i

3 0
3 years ago
?<br> What does the number, or density, of field lines on a source charge indicate?
Alenkinab [10]
The density of field lines on a source charge indicates the strength of the charge there is. The field lines all represent the movements of field charges. Naturally, if there are a large number of them compressed in an area, then that would mean the charge at that certain point is strong 
3 0
3 years ago
Read 2 more answers
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