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Ostrovityanka [42]
3 years ago
7

10.)A child-sized swimming pool can be modeled by a cylinder. The pool has a diameter of 6 1/2 feet and a height of 12 inches. T

he pool is filled with water to 2/3 of its height. Determine and state the volume of the water in the pool, to the nearest cubic foot. One cubic foot equals 7.48 gallons of water. Determine and state, to the nearest gallon, the number of gallons of water in the pool.
Mathematics
1 answer:
Luba_88 [7]3 years ago
8 0

Answer:

165.47≈165 Gallons of Water

Step-by-step explanation:

According To the Question,

  • Given, A child-sized swimming pool can be modeled by a cylinder. The pool has a diameter of 6 1/2 feet (or) 6.5 feet (radius is 3.25 feet) and a height of 12 inches(1 feet).

The pool is filled with water to 2/3 of its height (H= 2/3 feet) .

Volume of Cylinder = π×R²×H , now put values, we get

Volume = 3.14×3.25²×2/3

Volume = 22.122 foot³ .

And, One cubic foot equals 7.48 gallons of water

Thus, 22.122 cubic foot equals to 165.47≈165 gallons of water .

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Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

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Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

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Finding y-intercept

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y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

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Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

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