Question

HELP!!!! FAST!!!! 20 POINTS!!!! You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal
mass (3,000 kg each) were involved in a rear-end accident at a stop sign. Here is what you know:
• Truck 1 started from rest at the top of a 22-meter hill and coasted toward the intersection.
.
Truck 2 was on a flat stretch of road at the bottom of the hill directly in front of Truck 1.
At the bottom of the hill, Truck 1 was going 20 m/s; Truck 2 was going 35 m/s.
.
There were no skid marks left by Truck 2. The collision occurred at the stop sign where Truck 2 had
stopped
• After the collision, both trucks moved together in the same direction at 10 m/s before slowly rolling
to a stop.
You must now push Truck 2, using 1,000 N of force, 8 meters off to the side of the road so no one
else gets hurt.
1. What was the potential energy of Truck 1 at the top of the hill? 2. What was the kinetic energy of each truck before the began braking? 3. A. How much energy did truck 1 lose from the top to the bottom of the hill? B. Where do you suppose that energy went?

Answer 1

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1,  = = 20 m./s

Velocity of the truck 2, = 35 m./s

1. Kinetic energy of the truck 1:

Kinetic energy of the truck 2:

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height =  

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

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