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valentinak56 [21]
3 years ago
14

How do you solve this question? x^{3}-4x^{2}+4x-16

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0

Answer:

The answer will be ( x - 4 ) ( x^2 + 4 )

vodomira [7]3 years ago
7 0

Step-by-step explanation:

The picture is the answer. I hope this helped

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ZanzabumX [31]

Answer:

Step-by-step explanation:

\left[\begin{array}{ccc}7&31\\142&19\end{array}\right] = 7(19) - 142(31) = <em>- 4269</em>

\left[\begin{array}{ccc}7&11&21\\55&-8&2\\-16&-1&-9\end{array}\right] = 7(- 8)(- 9) + 11(2)(- 16) + 21(55)(- 1) - 21(- 8)(- 16) - 7(2)(- 1) - 11(55)(- 9) = <em>1768</em>

\left[\begin{array}{ccc}9.07&6.02&2.01\\-30.7&2.5&3.5\\3.55&-1.1&2.35\end{array}\right] = 9.07(2.5)(2.35) + 6.02(3.5)(3.55) + 2.01(- 30.7)(- 1.1) - 2.01(2.5)(3.55) - 9.07(3.5)(- 1.1) - 6.02(- 30.7)(2.35) = <em>647.3561</em>

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3 years ago
A local little has a total of 60 players ,of whom 40%are right-handed how many are right handed
maks197457 [2]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
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Is (0,1) , (1,3) , (2,5), (3,7) a function?​
igomit [66]

Answer:

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Step-by-step explanation:

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4 years ago
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A candle has been burning for 20 min and is now 25 cm tall. In an hour it will be 10 cm tall. Which equation models the height y
stiv31 [10]

Answer:

(y - 25) = - 0.25(x - 20)

Step-by-step explanation:

Given that :

Height of candle after burning for 20 minutes = 25 cm

Height after burning for 1 hr (60 minutes) = 10 cm

Height (y) in cm of candle x minutes after being lit:

Using the equation :

(y - y1) = m(x - x1)

m = (change in y / change in x)

Change in height within 60 minutes :

Height at 20 minutes = 25cm

Height after an hour = 10

Change in height per hour = (25 - 10) = 15cm

Hence, m = change in height per minute

15cm / 60 = 0.25cm ( - 0.25) (decrease in height)

y1 = 25 ; x1 = 20

(y - y1) = m(x - x1)

(y - 25) = - 0.25(x - 20)

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3 years ago
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