All categories

3 years ago

In this double replacement reaction, which are the products? hcl + naoh —> ______?

Chemistry

2 answers:

Paladinen [302]3 years ago

6 0

Answer is NaCI + H2O

Anarel [89]3 years ago

3 0

The answer is: " NaCl + H₂O " ; (or; write as: " H₂O + NaCl " ) .
________________________________________________________
Specifically:
_________________________________________________________

    HCl + NaOH —> NaCl + H₂O ;   or; write as:

   NaOH + HCl —> H₂O + NaCl .
_______________________________________________________
            This type of "double-replacement" reaction is called "neutralization".

             Since we are adding a strong acid to a strong base (reactants), we know that the product will be: 1) a salt ; and 2) water. Since we know one of the reactants will be "water" (H₂O) ; we can find the base (i.e. , the "remaining product") from selecting the "unused elements" to form the corresponding "salt".
________________________________________________________

You might be interested in

What is the best chemistry science fair project

nlexa [21]

Investigate The Kinetics Of The Amazing Iodine Clock Reaction

7 0

3 years ago

What is the atomic mass equal to?

mixer [17]

Atomic mass is equal to the total number of electrons neutrons and protons

8 0

3 years ago

Read 2 more answers

How many moles of electrons is required to deposit 5.6g of iron from a solution of iron (2) tetraoxosulphate(6)

yuradex [85]

Answer:

0.20 mol

Explanation:

Let's consider the reduction of iron from an aqueous solution of iron (II).

Fe²⁺ + 2 e⁻ ⇒ Fe

The molar mass of Fe is 55.85 g/mol. The moles corresponding to 5.6 g of Fe are:

5.6 g × 1 mol/55.85 g = 0.10 mol

2 moles of electrons are required to deposit 1 mole of Fe. The moles of electrons required to deposit 0.10 moles of Fe are

0.10 mol Fe × 2 mol e⁻/1 mol Fe = 0.20 mol e⁻

7 0

3 years ago

You're legally obligated to yield the right-of-way:

kenny6666 [7]

It is most likely B.

3 0

3 years ago

The most likely van't Hoff factor for an 0.01 m calcium iodide solution is

monitta

This problem is providing us with the molality of a solution of calcium iodide as 0.01 m. So the most likely van't Hoff factor is required and theoretically found to be 3 due to the following:

<h3>Van't Hoff factor:</h3>

In chemistry, the correct characterization of solutions also imply the identification of the ions it will release in aqueous solution. For that reason, the van't Hoff factor gives us an idea of this number, according to the formula the solute has got.

In such a way, for calcium iodide, we write its ionization equation as shown below:

$CaI_2\rightarrow Ca^{2+}+2I^-$

Assuming it is able to ionize due to the low molality, because if it was higher, then it won't ionize. Hence, since we have three moles of ion products, one Ca²⁺ and two I⁻, we can conclude the van't Hoff factor would be 3, although calculations may lead to a different, yet close result.

Learn more about the van't Hoff factor: brainly.com/question/23764376

5 0

2 years ago