3 years ago

5. What is the name of the Scientist who began classification?

Physics

2 answers:

mamaluj [8]3 years ago

3 0

Answer:

Carl Linnaeus discovered Classification

OleMash [197]3 years ago

3 0

Answer:

Carl Linnaeus

Explanation:

Mark me Brainllest

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Psychophysics is a discipline in psychology that focuses solely on the identification of stimuli. T F

Rzqust [24]

Hi There,

This is False.
Hope this helped!

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3 years ago

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What does temperature actually measure?

Alborosie

Temperature is measured with a thermometer

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4 years ago

An object with a mass of 2.0 kg accelerates 2.0 m/s 2when an unknown force is applied to it. What is the amount of force?

Musya8 [376]

Answer:

4 N

Explanation:

mass = 2 kg

acceleration = 2 m/s^2

Force = mass * acceleration

= 2 *2

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3 years ago

A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it

mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

$radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm$

$r = 0.145\ cm = 0.145\times 10^{-2}\ m$

Charge ,

$Q = 30.0\ pC=30\times 10^{-12}$

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

$V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}$

Where,

V= Electric potential,

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge

r = Radius

Substituting the values we get

$V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}$

$V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt$

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0

4 years ago

A 1500kg car is at rest before it accelerates when the light turns green. If it covers 45.0 meters in 15.0 seconds, what is the

lana [24]

Answer:

300N

Explanation:

Given parameters:

Mass of car = 1500kg

Initial velocity = 0m/s

Distance covered = 45m

Time = 15s

Unknown:

Net force applied = ?

Solution:

From Newton's second law:

Force = mass x acceleration

Force = mass x $\frac{v - u}{t}$

v is the final velocity

u is the initial velocity

t is the time taken

Final velocity = $\frac{45}{15}$ =3m/s

Force = 1500 x $\frac{3 - 0}{15}$ = 300N

8 0

3 years ago