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3 years ago

Evaluate the scenarios and select the one that demonstrates the training principle overload.

Physics

2 answers:

Irina18 [472]3 years ago

8 0

Answer:

The answer is A.

Explanation:

The answer is A. because overload means to do more and Kai swims more and more every day.

matrenka [14]3 years ago

5 0

Answer:

B :)

Explanation:

:) JUST TRUST ME I GOT IT CORRECT

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NEED HELP ASAP

kakasveta [241]

Answer:

Wavelength!

Explanation:

At least I think? Or wavelength might be crest to crest! Sorry if I'm incorrect. Let me know how I did!

8 0

3 years ago

the taipei 101 in taiwan is a 1667-foot tall, 101-story skyscraper. the skyscraper is the home of the world's fastest elevator.

BabaBlast [244]

The power delivered by the motor lift in elevating the 10 passengers at the speed of 16.8 m/s is 205800 Watts

<h3>What is power? </h3>

Power is simply defined as the rate at which energy is consumed. It can be expressed mathematically as

Power (P) = Force (F) × velocity (v)

P = Fv

<h3>How to determine the force </h3>

Mass (m) = 1250 Kg
Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = ma

F = 1250 × 9.8

F = 12250 N

<h3>How to determine the power </h3>

Velocity (v) = 16.8 m/s
Force (F) = 12250 N

Power (P) =?

P = Fv

P = 12250 × 16.8

P = 205800 Watts

Learn more about power:

brainly.com/question/5684937

6 0

2 years ago

An archer pulls back the string of a bow to release an arrow at a target. Which kind of potential energy is transformed to cause

Morgarella [4.7K]

It is elastic energy

8 0

4 years ago

Read 2 more answers

A catapult with a radial arm 3.81 m long accelerates a ball of mass 18.2 kg through a quarter circle. The ball leaves the appara

saw5 [17]

Answer:

(a) $\alpha = 53.73 m/s^2$

(b) I =428 $kgm^2$

(c) $\tau = 428 \times 53.73 = 22996 .44Nm$

Explanation:

GIVEN

mass = 18.2 kg

radial arm length = 3.81 m

velocity = 49.8 m/s

mass of arm = 22.6 kg

we know using relation between linear velocity and angular velocity

$\omega = \frac{v}{l}$

$\omega = \frac{49.8}{3.81} \\\omega = 12.99 rad/s$

for angular acceleration, use the following equation.

$\omega _{f}^2 = \omega_{i}^2+2\alpha\theta$

since $\omega _{i} = 0$

here for one circle is 2 π radians. therefore for one quarter of a circle is π/2 radians

so for one quarter $\theta = \frac{\pi }{2}$

$(12.99)^2 = 2\alpha(\frac{\pi }{2})$

on solving

$\alpha = \frac{168.74}{\pi }\\\alpha = 53.73 m/s^2$

(b)

For the catapult,

moment of inertia

$I = \frac{1}{2}MR^2$

$I = \frac{1}{2} \times 22.6\times 3.81 \times 3.81\I = 164kg m^2$

For the ball,

$I = MR^2$

$I = 18.2 \times 14.51$

$I = 264 kgm^2$

so total moment of inertia = 428 $kgm^2$

(c)

$\tau = I\alpha$

$\tau = 428 \times 53.73 = 22996 .44Nm$

3 0

4 years ago

The density of water is 10*3 kg/m*3. the water pressure on a submarine is 2.0 x 10*7 N/m*2. The depth of the submarine below the

Marat540 [252]

Answer:

2000metres

Explanation:

Pressure= density x height x gravity

Gravity is always a constant = 10N/kg

so height= Pressure/( density x gravity)

h= 20000000/(1000 x10)

h= 2000 metres

8 0

3 years ago