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saw5 [17]
3 years ago
10

Evaluate the scenarios and select the one that demonstrates the training principle overload.

Physics
2 answers:
Irina18 [472]3 years ago
8 0

Answer:

The answer is A.

Explanation:

The answer is A. because overload means to do more and Kai swims more and more every day.

matrenka [14]3 years ago
5 0

Answer:

B :)

Explanation:

:) JUST TRUST ME I GOT IT CORRECT

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What happens to the rock structure during each of type of change?
EastWind [94]
Previous rocks melt and collide and to form igneous rocks.
Igneous rocks disintegrate due to weather disruptions and get carried away by water, where they form sedimentary rock strata by lithification.
Igneous and sedimentary change by heat and pressure to form metamorphic rocks.
Metamorphic rocks melt and become igneous rocks.
3 0
3 years ago
Suppose an electron is trapped within a small region and the uncertainty in its position is 24.0 x 10-15 m. What is the minimum
Alina [70]

Answer:

  • Uncertainty in position (∆x) = 24 × 10⁻¹⁵ m
  • Uncertainty in momentum (∆P) = ?
  • Planck's constant (h) = 6.26 × 10⁻³⁴ Js

\longrightarrow \:  \:  \sf\Delta x .\Delta p =  \dfrac{h}{4\pi}

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34}} {4 \times  \frac{22}{7} }

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34}} { \frac{88}{7} }

\longrightarrow \:  \:  \sf24 \times  {10}^{ - 15}  .\Delta p =  \dfrac{6.26 \times  {10}^{ - 34} \times 7} { 8 }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34} } { 8  \times 24 \times  {10}^{ - 15} }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34} } { 192 \times  {10}^{ - 15} }

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ - 34}  \times  {10}^{15} } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{43.82 \times  {10}^{ -19}   } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{4382 \times  {10}^{ - 2}  \times  {10}^{ -19}   } { 192}

\longrightarrow \:  \:  \sf\Delta p =  \dfrac{4382 \times  {10}^{ - 21}   } { 192}

\longrightarrow \:  \:  \sf\Delta p = 22.822\times  {10}^{ - 21}

\longrightarrow \:  \:  \sf\Delta p = 2.2822 \times  {10}^{1} \times  {10}^{ - 21}

\longrightarrow \:  \: \underline{ \boxed{ \red{  \bf\Delta p = 2.2822 \times  {10}^{ - 20}  \:  kg/ms}}}

4 0
2 years ago
5 x 10 to the power electron cross through the cross section of a wire per second. What is the magnitude of electric current pas
Rom4ik [11]

. She replaces a straight electrical

8 0
3 years ago
Mr. Jones starts from rest and begins to accelerate straight to the bathroom at a rate of 0.5 m/s for 10 seconds. What kind of m
Xelga [282]

Answer:

A. linear

Explanation:

because they are going in a straight line

5 0
2 years ago
Using a 2.44kg sledge hammer, a railroad worker drives a 0.55kg spike into a railroad tie. The sledge hits the spike with a spee
Mazyrski [523]

Answer:

1547.6 J

Explanation:

From the law of conservation of energy, the sum of initial and final energy is the same. Energy can only be transformed into other forms but can't be created nor lost

Initial kinetic energy of the hammer system is given by

KE_i=0.5mv^{2} where m is mass of the body and v is the velocity

Substituting m for mass of hammer which is 2.44 Kg and v for 62 m/s

KE_i=0.5*2.44 Kg*(62 m/s)^{2}=4689.68 J

Since the hammer comes to rest, the final kinetic energy is zero since it's velocity is zero

KE_f=0 J

Change in kinetic energy is given by

\triangle KE= KE_f-KE_i hence 0-4689.68  J=-4689.68  J

Change in total internal energy is given by

\triangle PE-\triangle KE and in this case the change in potential energy is zero

\triangle PE-\triangle KE=0--4689.68 J=4689.68 J

Since only 0.33 of this energy is converted hence

0.33\times4689.68 J=1547.5944 J\approx 1547.6 J

6 0
3 years ago
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