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saw5 [17]
3 years ago
10

Evaluate the scenarios and select the one that demonstrates the training principle overload.

Physics
2 answers:
Irina18 [472]3 years ago
8 0

Answer:

The answer is A.

Explanation:

The answer is A. because overload means to do more and Kai swims more and more every day.

matrenka [14]3 years ago
5 0

Answer:

B :)

Explanation:

:) JUST TRUST ME I GOT IT CORRECT

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Is it possible that a speed of 254 and a speed of 100 could be the same speed?
EastWind [94]
Not if both speeds are in the same units.

However, if the 254 is 'centimeters per time' and the 100 is 'inches per time',
then the speeds are equal.
4 0
3 years ago
The rate at which work is done is called ____.
alekssr [168]
D. Power. The unit of power is watt.
6 0
3 years ago
If a runner has a speed of 8.66m/s and runs for 46.2s what distance is covered? tv = d
kati45 [8]

Answer:

\text{Using the formula: }v=\frac{d}{t}\\\therefore vt=d\\\text{Plug and chug:}46.2(8.66)=400.092\text{ metres}

6 0
3 years ago
How do two objects at different temperatures attain thermal equilibrium?
Lady bird [3.3K]

Answer:

C.As the two objects touch, thermal energy flows as heat from the warmer block to the colder block until particles in both blocks move at the same rate and reach the same temperature.

Explanation:

Heat is the transfer of thermal energy from an object at higher temperature to an object at colder temperature.

The temperature of an object is a measure of how fast the particles in the object move: the higher its temperature, the faster the particles move, the higher the average kinetic energy of the particles in the object. As a result, the particles of the object at higher temperature tend to transfer more energy (called thermal energy) to the particles of the object at colder temperature by colliding with them: this process continues until the particles of the colder object reach the same average kinetic energy as the particles of the warmer object, and this means that the two objects have reached the same temperature.

3 0
3 years ago
Part complete Sound with frequency 1240 Hz leaves a room through a doorway with a width of 1.11 m . At what minimum angle relati
Sedbober [7]

Answer:

14.43° or 0.25184 rad

Explanation:

v = Speed of sound in air = 343 m/s

f = Frequency = 1240 Hz

d = Width in doorway = 1.11 m

Wavelength is given by

\lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{343}{1240}\\\Rightarrow \lambda=0.2766\ m

In the case of Fraunhofer diffraction we have the relation

dsin\theta=\lambda\\\Rightarrow \theta=sin^{-1}\frac{\lambda}{d}\\\Rightarrow \theta=sin^{-1}\frac{0.2766}{1.11}\\\Rightarrow \theta=14.43^{\circ}\ or\ 0.25184\ rad

The minimum angle relative to the center line perpendicular to the doorway will someone outside the room hear no sound is 14.43° or 0.25184 rad

6 0
3 years ago
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