Answer:
Mole fraction of solute is 0.0462
Explanation:
To solve this we use the colligative property of lowering vapor pressure.
First of all, we search for vapor pressure of pure water at 25°C = 23.8 Torr
Now, we convert the Torr to mmHg. Ratio is 1:1, so 23.8 Torr is 23.8 mmHg.
Formula for lowering vapor pressure is:
ΔP = P° . Xm
Where ΔP = P' (Vapor pressure of solution) - P° (Vapor pressure of pure solvent)
Xm = mole fraction
24.9 mmHg - 23.8 mmHg = 23mmHg . Xm
Xm = (24.9 mmHg - 23.8 mmHg) / 23mmHg
Xm = 0.0462
Answer:
Explanation:
It may not make any difference. The information missing is the radius of the planet.
However for the purposes of the question, let us assume that it is roughly the same diameter of the earth. Then the weight of anyone would increase if the mass is all that changes..
The formula governing your weight is F = G * m1 *m2 / r^2. If m1 is the mass of the planet and it increases a lot then m2 (you) should increase. The question is done by a proportion.
KE=1/2*mass*velocity^2
So u do 1/2 * 1 * 30^2
1/2 * 1 * 900
= 450kgm/s
P.s. I'm not sure if I would have to convert kg to g.
Anyways hope this helped
Eutrophication results from an excess of
a. phosphates
To solve this problem, let us all convert the mass of
each element into number of moles using the formula:
moles = mass / molar mass
Where,
molar mass K = 39.10 g / mol
<span>molar mass Cl = 35.45 g / mol</span>
molar mass O = 16 g / mol
<span>and mass O = 13 g – 4.15 g
– 3.76 g = 5.09 g</span>
moles K = 4.15
g / (39.10 g / mol) = 0.106 mol
<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>
moles O = 5.09 g / (16 g /
mol) = 0.318 mol
The ratio becomes:
0.106 K: 0.106 Cl: 0.318 O
We divide all numbers with
the smallest number, in this case 0.106. This becomes:
K: Cl: 3O
Therefore the empirical formula
is:
