The person above me is correct
Answer:
0.6 moles of Fe
Explanation:
Given data:
Number of atoms of Fe = 3.612×10²³
Number of moles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
From atoms to mole:
3.612×10²³ atoms of Fe × 1 mole / 6.022 × 10²³ atoms
0.6 moles of Fe
Answer:
![[N_2]=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3D0.0866M)
Explanation:
Hello there!
In this case, in agreement to the chemical reaction, it is possible for us to figure out the equilibrium concentration of the N2 product, via an ICE table plugged in the equilibrium expression:
![Kc=\frac{[N_2][O_2]}{[NO]^2}\\\\2.4x10^3=\frac{x*x}{(0.175-2x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BN_2%5D%5BO_2%5D%7D%7B%5BNO%5D%5E2%7D%5C%5C%5C%5C2.4x10%5E3%3D%5Cfrac%7Bx%2Ax%7D%7B%280.175-2x%29%5E2%7D)
In such a way, when solving for x via quadratic equation or just a solver, it is possible to obtain:

In such a way, since the root 0.0884 M produce a negative concentration of NO (0.175-2*0.0884=-0.0018M), we infer that the correct root is 0.0866 M; therefore, the concentration of N2 at equilibrium is equal to x:
![[N_2]=x=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3Dx%3D0.0866M)
Best regards!
Answer:
thanks for your points
God bless you ALWAYS
and pa follow
at pa brainlest answer please
You are given
300 grams of FeCr2O7. You are required to get the mass of O2 in grams. The first
thing to do is to find a reaction between FeCr2O7 and O2. The balanced chemical
reaction is 2Fe + 6Cr + 21/2O2 -> Fe2(Cr2O7)3. The molar mass of Fe2(Cr2O7)3
is 759.65 grams per mole and 32 grams per mole for O2.
<span>
300g Fe2(Cr2O7)3
(1 mol Fe2(Cr2O7)3/759.65 g Fe2(Cr2O7)3)(21/2 mol O2/1 mole Fe2(Cr2O7)3)(32 g
O2/1 mole O2) = <u>132.7 g O2</u></span>