Using ideal gas formula (PV=nRT), you can conclude that volume directly related to the temperature. That means an increase in temperature will cause an increased volume too. Note that the temperature is using Kelvin, not Celsius. The calculation would be:
V1/T1= V2/T2
590ml / (-<span>55+ 273)K = V2/ (30+273)K
V2= (590ml/ 218K) * 303K
V2= 820ml</span>
Answer:
C5H12 + 8O2 --> 5CO2 + 6H2O
Explanation:
Complete question
Write a balanced chemical equation to represent the combustion of CH3CH2CH2CH2CH3
Solution
The given compound is pentane
C5H12
The empirical equation representing combustion of pentane is
C5H12 + O2 --> CO2 + H2O
We will first balance the carbon atoms
C5H12 + O2 --> 5CO2 + H2O
Now we will balance the Hydrogen molecule
C5H12 + O2 --> 5CO2 + 6H2O
Now we will balance the oxygen molecule
C5H12 + 8O2 --> 5CO2 + 6H2O
Answer:
The higher the vapor pressure of a liquid at a given temperature, the lower the normal boiling point of the liquid.
Explanation:
Answer:
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