The answer to the question asked above is heat energy<span> .
</span><span>The energy powering the movements of molecules is referred to as the heat energy of the system.</span>
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The amount of barium ions that must be present in order for the salt to precipitate is 0.245 M.
A solution's solubility product is the result of raising each ion's concentration to the power of its stoichiometric ratio. It is portrayed as
A combination of 1 barium ion and 2 fluoride ions results in the ionic compound known as barium fluoride.
The following equation describes the equilibrium reaction for barium fluoride ionization:
BaF₂ → Ba²⁺ + 2F⁻
Ksp = [Ba²⁺] · [F⁻]²
2.45*
= [Ba²⁺] * ![[1. 00*10^{-2} ]^{2}](https://tex.z-dn.net/?f=%5B1.%2000%2A10%5E%7B-2%7D%20%5D%5E%7B2%7D)
[Ba²⁺]=0.245 M
As a result, 0.245 M of barium ions must be present in order for the salt to precipitate.
<h3>Solubility </h3>
Solubility in chemistry refers to a chemical's capacity to dissolve in another substance, the solvent, to produce a solution. Inability of the solute to create such a solution is the opposite quality, or insolubility. A substance's degree of solubility in a given solvent is often determined by the amount of the solute present in a saturated solution, which is a solution in which no additional solute can be dissolved. The solubility equilibrium between the two compounds is considered to have been reached at this time. If there is no such restriction for a given solute and solvent, the two are referred to as being "miscible in any amounts."
What concentration of the barium ion, ba2 , must be exceeded to precipitate baf2 from a solution that is 1. 00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2. 45×10−5
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<span>83.9%
First, determine the molar masses of Al(C6H5)3 and C6H6. Start by looking up the atomic weights of the involved elements.
Atomic weight aluminum = 26.981539
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Molar mass Al(C6H5)3 = 26.981539 + 18 * 12.0107 + 15 * 1.00794 = 258.293239 g/mol
Molar mass C6H6 = 6 * 12.0107 + 6 * 1.00794 = 78.11184 g/mol
Now determine how many moles of C6H6 was produced
Moles C6H6 = 0.951 g / 78.11184 g/mol = 0.012174851 mol
Looking at the balanced equation, it indicates that 1 mole of Al(C6H5)3 is required for every 3 moles of C6H6 produced. So given the number of moles of C6H6 you have, determine the number of moles of Al(C6H5)3 that was required.
0.012174851 mol / 3 = 0.004058284 mol
Then multiply by the molar mass to get the number of grams that was originally present.
0.004058284 mol * 258.293239 g/mol = 1.048227218 g
Finally, the weight percent is simply the mass of the reactant divided by the total mass of the sample. So
1.048227218 g / 1.25 g = 0.838581775 = 83.8581775%
And of course, round to 3 significant digits, giving 83.9%</span>
In H2O molecule, two water molecules are bonded by a Hydrogen bond but the bond between two H - O bonds within a water molecule are covalent
Each enzyme's active site is suitable for one specific type of substrate – just like a lock that has the right shape for only one specific key. Changing the shape of the active site of an enzyme will cause its reaction to slow down until the shape has changed so much that the substrate no longer fits.
