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wolverine [178]
3 years ago
8

What volume of 18.5 M nitric acid would be needed to make 25.0 mL of 3.0M?

Chemistry
1 answer:
Firdavs [7]3 years ago
5 0

Answer:What volume of 9.00 M nitric acid is needed to make 6.50 L of 1.25 M solution? 903 mL What molarity should the stock solution be if you want to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103 M?

Explanation:

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Calculate the molar solubility of CaF2 at 25°C in a solution that is 0.010 M in Ca(NO3)2. The Ksp for CaF2 is 3.9 x 10-11.
madreJ [45]

Answer:

Molar \ solubility=3.12x10^{-5}M

Explanation:

Hello,

In this case, for the dissociation of calcium fluoride:

CaF_2(s)\rightleftharpoons Ca^{2+}+2F^-

The equilibrium expression is:

Ksp=[Ca^{2+}][F^-]^2

In such a way, via the ICE procedure, including an initial concentration of calcium of 0.01 M (due to the calcium nitrate solution), the reaction extent x is computed as follows:

3.9x10^{-11}=(0.01+x)(2*x)^2\\\\x=0.0000312M

Thus, the molar solubility equals the reaction extent x, therefore:

Molar \ solubility=3.12x10^{-5}M

Regards.

4 0
3 years ago
How are coefficients used to balance chemical equations?
Zepler [3.9K]
According to the law of conservation of mass, the quantity of the elements, involved in chemical reactions does not change. For example,
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2H2O2 - > 2H2O + O2
4 0
3 years ago
you know the mass of an object and the force applied to the bject to make it move . Which of Newtons laws of motion will help yo
MAVERICK [17]

Answer:

second law of acceleration

Explanation:

hope this helps :)

8 0
3 years ago
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Please help<br><br>Differentiate between the three systems of rearing pigs.​
natulia [17]

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5 0
3 years ago
A swimming pool is 5.0 m long, 4.0 m wide and 3.0 m deep. Compute the force exerted by the water against
Alona [7]
For the answer to the question above, <span>ater weights 1000kg per meter cubed. the volume of the pool is part A is 5*4*3 = 60 meters cubed </span>
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<span>part B: </span>
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<span>48 * 1000 = 48000kg </span>
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I hope this helps.</span>
6 0
3 years ago
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