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wolverine [178]
3 years ago
8

What volume of 18.5 M nitric acid would be needed to make 25.0 mL of 3.0M?

Chemistry
1 answer:
Firdavs [7]3 years ago
5 0

Answer:What volume of 9.00 M nitric acid is needed to make 6.50 L of 1.25 M solution? 903 mL What molarity should the stock solution be if you want to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103 M?

Explanation:

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What do you think would happen if you placed a drop of iodine on your baked potato at dinner?
DiKsa [7]

Answer:there is visible blue black coloration

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Starch consist of two distinguishable polysaccharide fraction namely amylose and amylopectin.

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A ) 1, 2 and 3

Explanation:

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8 0
2 years ago
Read 2 more answers
For the chemical equation SO 2 ( g ) + NO 2 ( g ) − ⇀ ↽ − SO 3 ( g ) + NO ( g ) the equilibrium constant at a certain temperatur
Ipatiy [6.2K]

Answer : The number of moles of NO_2 gas added must be, 1.59 moles.

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

The given equilibrium reaction is,

                        SO_2(g)+NO_2(g)\rightleftharpoons SO_3(g)+NO(g)

Initial conc.    2.86               x             0          0

At eqm.       (2.86-1.30)    (x-1.30)     1.30     1.30

The expression of K_{eq} will be,

K_{eq}=\frac{[SO_3][NO]}{[SO_2]NO_2]}

Now put all the given values in this expression, we get:

3.70=\frac{(1.30)\times (1.30)}{(2.86-1.30)\times (x-1.30)}

x=1.59

Thus, the number of moles of NO_2 gas added must be, 1.59 moles.

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