Answer is: 16,56 kJ.
1) m(NH₄Cl) = 5,35g.
m(H₂O) = d(H₂O) · V(H₂O) = 1g/cm³ · 100cm³ = 100g.
ΔT = 25,55°C - 21,79°C = 3,76°C.
Q = m(solution) · C(specific heat capacity of water) ·ΔT.
Q = 105,35g · 4,18 J/g·°C · 3,76°C = 1655,76J.
2) m(NH₄Cl) = 1mol · 53,5g/mol = 53,5g.
m(water) = d(H₂O) · V(H₂O) = 1g/cm³ · 1000cm³ = 1000g.
m(solution) = 1053,5g, ten times more than first solutn.
Q = 10 · 1655,76J = 16557,6J = 16,56 kJ.
Answer:
b
Explanation:
b because it's a physical change
