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2 years ago

fill in the blanks: label the different parts of the rock cycle where igneous, sedimentary, and metamorphic rock are formed.

Chemistry

1 answer:

Zarrin [17]2 years ago

6 0

Answer:

☞rock cycle

=> The rock cycle is a basic concept in geology that describes transitions through geologic time among the three main rock types: sedimentary, metamorphic, and igneous. Each rock type is altered when it is forced out of its equilibrium conditions.

=> There are three main kinds of rocks: igneous rock, metamorphic rock, and sedimentary rock. ... It can erode into sediment or melt into magma. It is formed under extreme pressure and temperature deep inside mountain chains.

Explanation:

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When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coeffici

maxonik [38]

Answer:

1. Al2O3 + 3H2SO4 —> Al2(SO4)3 + 3H2O

The coefficients are: 1, 3, 1, 3

2. Yes, reaction occurs when ammonium carbonate and chromium(III) nitrate are combined.

The balanced equation for the reaction is given below:

3(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

The coefficients are: 3, 2, 6, 1

Explanation:

1. The word equation is given below:

aluminum oxide(s) + sulfuric acid(aq) -> aluminum sulfate(aq) + water (l)

The above can be written as:

Al2O3 + H2SO4 —> Al2(SO4)3 + H2O

Now we can balance the equation as follow:

There are 3 atoms of SO4 on the right side and 1 atom on the left. It can be balance by putting 3 in front of H2SO4 as shown below:

Al2O3 + 3H2SO4 —> Al2(SO4)3 + H2O

There are 6 atoms of H on the left side and 2 atoms on the right. It can be balance by putting 3 in front of H2O as shown below:

Al2O3 + 3H2SO4 —> Al2(SO4)3 + 3H2O

Now the equation is balanced

The coefficients are: 1, 3, 1, 3

2. Yes, reaction occurs when ammonium carbonate and chromium(III) nitrate are combined.

The equation for the reaction is given below:

(NH4)2CO3 + Cr(NO3)3 —> NH4NO3 + Cr2(CO3)3

We can balance the equation above as follow:

There are 2 atoms of Cr on the right side and 1 atom on the left. It can be balance by putting 2 in front of Cr(NO3)3 as shown below:

(NH4)2CO3 + 2Cr(NO3)3 —> NH4NO3 + Cr2(CO3)3

Now, there are 6 atoms of NO3 on the left side and 1 on the right side. It can be balance by putting 6 in front of NH4NO3 as shown below:

(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

Now, there are 2 atoms of NH4 on the left side and 6 atoms on the right. It can be balance by putting 3 in front of (NH4)2CO3 as shown below:

3(NH4)2CO3 + 2Cr(NO3)3 —> 6NH4NO3 + Cr2(CO3)3

Now the equation is balanced.

The coefficients are: 3, 2, 6, 1

7 0

4 years ago

Which of the following are bound to hemoglobin when hemoglobin is in the r-state? choose all that apply.

Mademuasel [1]

Even though there is no followings, I will try to include in this answer all the possible answers. I am sure about two elements that bound to hemoglobin when hemoglobin is in the R-state :Fe+2 and O2. As you should know, <span> R-state of hemoglobin is a relaxed form that is also called</span> <span>oxyhemoglobin, so the O2 definitely must be mentioned in there.</span>

7 0

3 years ago

rite an equation for the formation one mole of CaCO3(s) from its elements in their standard states. Write any reference to carbo

maks197457 [2]

Answer: The chemical equation for the formation one mole of $CaCO3(s)$ from its elements in their standard states is $Ca(s)+C(s)+\frac{3}{2}O_2(g)\rightarrow CaCO_3(s)$

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

The chemical equation for the formation one mole of $CaCO3(s)$ from its elements in their standard states is:

$Ca(s)+C(s)+\frac{3}{2}O_2(g)\rightarrow CaCO_3(s)$

where (s) represents solid state and (g) represents gaseous state.

6 0

4 years ago

Why is the energy supplied by the cooker greater than that calculated ?

TEA [102]

Answer:

Explanation:

Q1.

(a) 46 200

accept 46 000

allow 1 mark for correct substitution

ie 0.5 × 4200 × 22 provided no subsequent step

(b) Energy is used to heat the kettle.

[3]

Q2.

(a) (approximate same size particles as each other and as liquid and gas) touching

do not accept particles that overlap

regular arrangement (filling the square)

(b) condensing

(d) physical

(e) particles have more kinetic energy

particles move faster

(f) mass of the liquid

specific latent heat of evaporation

(g) 2 × 4 200 × 801

672 000 (J)

an answer of 672 000 (J) scores 2 marks

[11]

Q3.

(a) x-axis labelled and suitable scale

Page 12 of 13

points plotted correctly

allow 5 correctly plotted for 2 marks, 3−4

correctly plotted for 1 mark

allow ± ½ square

line of best fit

(b)

allow ecf from line of best fit in part (a)

0.075 (°C/s)

an answer of 0.075 (°C/s) scores 2 marks

a calculation using an incorrect temperature

scores max 3 marks

ΔE = 1.50 × 900 × 11.5

ΔE = 15 525 (J)

ΔE = 15.525 (kJ)

an answer of 15.525 (kJ) or 15.53 (kJ) or 15.5

(kJ) scores 4 marks

an answer of 15 525 (kJ) scores 3 marks

[10]

Q4.

(a) 80 °C

ΔE = 0.5 × 3400 × 80

ΔE = 136 000 (J)

an answer of 136 000 (J) scores 3 marks

(b) energy is dissipated into the surroundings

allow any correct description of wasted energy

allow any sensible practical suggestion

eg add salt to the water

Page 13 of 13

(d) efficiency = 300/500

efficiency = 0.6

an answer of 0.6 or 60% scores 2 marks

allow efficiency = 60%

an answer of 0.6 with a unit scores 1 mark

an answer of 60 without a unit scores 1 mark

7 0

3 years ago

Nonmetals are ___.

Shkiper50 [21]

Poor conductors of heat

5 0

3 years ago