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3 years ago

A list of different ions are below. Which combinations of ions will result in an ionic bond?

2 answers:

7 0

Ionic bond is a type of bond formed between a non metal and a metal, it involves transfer of electrons that results to formation of ions, normally a cation and an anion. In this case the combinations that will result to ionic bonds include;
NaF, LiCl, NaO2, BeF2, and BeS

Citrus2011 [14]3 years ago

6 0

Answer:

NaF, LiCl, NaO2, BeF2, and BeS

Explanation:

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Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 12,900 kg. The thrust of its engines is

Alexandra [31]

Answer:

Acceleration a=0.5 m/s²

Explanation:

Given data

Mass m=12,900 kg=1.29×10⁴kg

Thrust of engine F=28,000 N=2.8×10⁴N

gravitational acceleration g=1.67 m/s²

To find

Acceleration

Solution

As we know that

$W_{weigth}=mg\\ W=(1.29*10^{4}kg )(1.67m/s^{2} )\\W=21543N$

The net force can be given as

$F_{net}=F_{thrust}-W\\F_{net}=(2.8*10^{4}-21543)N\\ F_{net}=6457 N$

From Newtons second law of motion we know that

$F=ma\\a=F/m\\a=\frac{6457N}{12,900kg}\\ a=0.5m/s^{2}$

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3 years ago

Explain the relationship between the distance between the string and your elbow and the effort required to lift the mass.

MissTica

Answer:

Sorry I I’m a little lost

Explanation:

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3 years ago

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The electric field strength E₀ is measured at a perpendicular distance R from an infinitely large, thin sheet that contains a un

Troyanec [42]

Answer:

Explanation:

E=(σ/ε0)

As noted by Dirac the field is the same no matter how far you are from the sheet. When your charge covers a conducting plane, as in your case, the field is, D/eo ,(D is charge density). Because the field inside the conductor (no matter how thin) is zero. The only time the field is, D/2eo, is when you have just a sheet of charge, by itself, not on a conducting plane."

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4 years ago

_______is used as a magnifying glass to read very small print.

Alexus [3.1K]

Answer:

The answer is B

Explanation:

Concave lens

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2 years ago

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In 2017, the company SpaceX became the first private company to send supplies to the International Space Station with a reusable

pav-90 [236]

Answer:

Approximately $3.98\; \rm m \cdot s^{-2}$ .

Assumption: air resistance on the rocket is negligible. Take $g = \rm 9.81\; m \cdot s^{-2}$ .

Explanation:

By Newton's Second Law of Motion, the acceleration of the rocket is proportional to the net force on it.

$\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ .

Note that in this case, the uppercase letter $\rm M$ in the units stands for "mega-", which is the same as $10^6$ times the unit that follows. For example, $\rm 1\; Mg = 10^6\; g$ , while $\rm 1\; MN = 10^6\; N$ .

Convert the mass of the rocket and the thrust of its engines to SI standard units:

The standard unit for mass is kilograms: $\displaystyle m = \rm 552\; Mg = 552 \times 10^6\; g \times \frac{1\; \rm kg}{10^3\; g} = 552 \times 10^3 \; kg$ .
The standard for forces (including thrust) is Newtons: $\text{Thrust} = \rm 7.61 \; MN = 7.61 \times 10^6\; N$ .

At launch, the velocity of the rocket would be pretty low. Hence, compared to thrust and weight, the air resistance on the rocket would be pretty negligible. The two main forces that contribute to the net force of the rocket would be:

Thrust (which is supposed to go upwards), and
Weight (downwards due to gravity.)

The thrust on the rocket is already known to be $\rm 7.61 \times 10^6\; N$ . Since the rocket is quite close to the ground, the gravitational acceleration on it should be approximately $9.81\; \rm m \cdot s^{-2} = 9.81 \; N \cdot kg^{-1}$ . Hence, the weight on the rocket would be approximately $9.81\; \rm N \cdot kg^{-1} \times 552 \times 10^3\; kg = 5.41412\times 10^6\; N$ .

The magnitude of the net force on the rocket would be

$\begin{aligned}&\text{Thrust} - \text{Weight} \\ &= 7.61 \times 10^6\; \rm N - 5.41412\times 10^6\; N \\ &\approx 2.19 \times 10^6\; \rm N\end{aligned}$ .

Apply the formula $\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ to find the net force on the rocket. To make sure that the output (acceleration) is in SI units (meters-per-second,) make sure that the inputs (net force and mass) are also in SI units (Newtons for net force and kilograms for mass.)

$\begin{aligned}\displaystyle &\text{Acceleration} \\ &= \frac{\text{Net Force}}{\text{Mass}} \\ &= \frac{2.19 \times 10^6\; \rm N}{552 \times 10^3\; \rm kg} \\ &\approx \rm 3.98\; \rm m \cdot s^{-2}\end{aligned}$ .

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3 years ago