Answer:
Maximum height reached by the rocket, h = 202.62 meters
Explanation:
It is given that,
Initial speed of the model rocket, u = 56.5 m/s
Constant upward acceleration, 
Distance traveled by the engine until it stops, d = 198.8 m
Let v is the speed of the rocket when the engine stops. It can be calculated using the third equation of motion as :

v = 63.02 m/s
At the maximum height, v = 0 and the engine now decelerate under the action of gravity, a = -g. Let h is the maximum height reached by the rocket.
Again using third equation of motion as :




h = 202.62 meters
So, the maximum height reached by the rocket is 202.62 meters. Hence, this is the required solution.
Answer:
Explanation:
3 and 4G networks, Bluetooth, and Wi-Fi technologies. my opinions
To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as

Where
d = Distance
t = time
For which clearing the time we will have the expression

Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:


In the case of the atmosphere -composite of air- the average speed of sound is 343m / s, therefore it will take


The total difference between the two times would be


Therefore 3.357s will pass between when they feel the explosion and when they hear it
All you need to do is wrap some insulated copper<span> wire around an </span>iron<span> core. If you attach a battery to the wire, an electric current will begin to flow and the iron core will become magnetized. When the battery is disconnected, the iron core will lose its magnetism.</span>
Answer:
D. 48.985 N
Explanation:
Newton's second law states that:

which means that the net force acting on an object is equal to the product between the object's mass and its acceleration.
The equation of the forces for the briefcase in the elevator therefore is given by:

where
N is the normal reaction exerted on the briefcase
(mg) is the weight of the briefcase, with
m = 4.5 kg being its mass
g = 9.8 m/s^2 is the acceleration of gravity
a = 1.10 m/s^2 is the acceleration
Here we chose upward as positive direction.
Solving for N, we find the normal force:

So the closest answer is
D. 48.985 N