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2 years ago

Which sentence accurately uses the homophones “they’re,” “there,” or “their”?

Physics

2 answers:

Inessa05 [86]2 years ago

4 0

Answer:

They're going to come home as soon as the movie is over.

AleksAgata [21]2 years ago

3 0

Answer:

B: They're going to come home as soon as the movie is over.

Explanation:

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Which one of the following is not equivalent to 2.50 miles?

lisabon 2012 [21]

Answer:

Choice C is not equivalent to 2.50 miles.

Explanation:

The given data is now converted into feet, inches, kilometers, yards and centimeters:

mi - ft

$x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi} \right)$

$x = 13200\,ft$

$x = 1.320\times 10^{4}\,ft$ (Choice A)

mi - in

$x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi} \right)\cdot \left(12\,\frac{in}{ft} \right)$

$x = 158400\,in$

$x = 1.584\times 10^{5}$ (Choice B)

mi - km

$x = (2.50\,mi)\cdot \left(1.61\,\frac{km}{mi} \right)$

$x = 4.025\,km$ (Different from Choice C)

mi - yd

$x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi}\right) \cdot \left(\frac{1}{3}\,\frac{yd}{ft} \right)$

$x = 4400\,yd$

$x = 4.40\times 10^{3}\,yd$ (Choice D)

mi - cm

$x = (2.50\,mi)\cdot \left(1.61\,\frac{km}{mi} \right)\cdot \left(100000\,\frac{cm}{km}\right)$

$x = 402500\,cm$

$x = 4.025\times 10^{5}\,cm$ (Choice E)

Choice C is not equivalent to 2.50 miles.

6 0

3 years ago

A circuit consists of a 12 V battery connected across a single resistor. If the current in the circuit is

finlep [7]

Answer:

4 Ohms

Explanation:

Apply the formula:

Voltage = I (current) . Resistance

You can change it the way you want to use for your purpose.

In this case...

R = V/I

R = 12/3

R = 4 Ohms (Ohm is the unit of measurement of eletrical resistance)

7 0

2 years ago

The curved line PQR is the velocity-time graph for a car starting from rest.

Elden [556K]

His. Curbs I b h bs. H b u b

3 0

3 years ago

What should a scientist do if the results and data do not support his/her hypothesis?

german

Answer: If it does not support the hypothesis, you may choose to change the hypothesis or write a new one based on what was learned during the experiment.

Hypothesize a new answer to the question and a new way to test it.

Explanation:

8 0

2 years ago

How to understand that an inductor behaves like short circuit and capacitor like an open circuit in steady state in a network?

garik1379 [7]

It depends on the steady-state frequency. At zero frequency an inductor behaves like an open circuit. As the frequency increases, the inductor acts more like an open circuit and a capacitator acts more like a short circuit

8 0

3 years ago