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devlian [24]
3 years ago
7

WILL GIVE BRAINLIEST PLZ HURRY!!!!

Physics
1 answer:
NISA [10]3 years ago
8 0

When an object is having variable velocity then we can use the definition of acceleration to find it that rate of change in velocity is known as acceleration.

We can define it as

a = \frac{v_f - v_i}{\Delta t}

here

v_f = final velocity

v_i = initial velocity

\Delta t = time interval

now it is given here that final velocity is less than initial velocity after some time which means

v_f < v_i

so here we can say acceleration will have negative value which shows it is opposite to the direction of velocity.

So this is the case of decreasing velocity which is known as <u>deceleration</u>.

So correct answer is

<u>deceleration</u>

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A pendulum with a length of 1 meter is released from an initial angle of 15.0° after 1000s its amplitude has been reduced by fri
Setler [38]

Answer:

0.366×10^{-3} / s

Explanation:

θ = θmax e^{-bt/2m}

Given that

             θ = 5.50°

             θmax = 15.0°

So that we have

                ln (θ / θmax) = -bt /2m

            = - ln(5.50°/ 15.0°) / 1000s = b /2m

             = b / 2m = 0.366×10^{-3} / s

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3 years ago
What timeis the name of the units that
Westkost [7]

Answer:

Joule is the name of the unit that are normally used to measure energy

Explanation:

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2 years ago
Under what circumstances does distance traveled equal magnitude of displacement? What is the only case in which magnitude of dis
Sedaia [141]

Answer: Please find the answer in the explanation

Explanation:

Under what circumstances does distance traveled equal magnitude of displacement?

When a body's motion is linear in one direction. Or a body moving in a straight line without turning back.

What is the only case in which magnitude of displacement and distance are exactly the same?

When the body is moving in a straight line with without changing direction or without turning back.

6 0
3 years ago
Calculation using Ohm's Law: If a circuit has a voltage of 500 V and a resistance of 250 ohms, what is the current?
konstantin123 [22]

I = V / R

Current = (voltage) / (resistance)

Current = (500 V) / (250 ohms)

Current = (500/250) Amperes

<em>Current = 2 Amperes</em>

6 0
3 years ago
Read 2 more answers
An airplane is moving at 350 km/hr. If a bomb is
Molodets [167]

Answers:

a) -171.402 m/s

b) 17.49 s

c) 1700.99 m

Explanation:

We can solve this problem with the following equations:

y=y_{o}+V_{oy}t-\frac{1}{2}gt^{2} (1)

x=V_{ox}t (2)

V_{f}=V_{oy}-gt (3)

Where:

y=0 m is the bomb's final jeight

y_{o}=1.5 km \frac{1000 m}{1 km}=1500 m is the bomb'e initial height

V_{oy}=0 m/s is the bomb's initial vertical velocity, since the airplane was moving horizontally

t is the time

g=9.8 m/s^{2} is the acceleration due gravity

x is the bomb's range

V_{ox}=350 \frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=97.22 m/s is the bomb's initial horizontal velocity

V_{f} is the bomb's fina velocity

Knowing this, let's begin with the answers:

<h3>b) Time</h3>

With the conditions given above, equation (1) is now written as:

y_{o}=\frac{1}{2}gt^{2} (4)

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (5)

t=\sqrt{\frac{2 (1500 m)}{9.8 m/s^{2}}} (6)

t=17.49 s (7)

<h3>a) Final velocity</h3>

Since V_{oy}=0 m/s, equation (3) is written as:

V_{f}=-gt (8)

V_{f}=-(97.22)(17.49 s) (9)

V_{f}=-171.402 m/s (10) The negative sign ony indicates the direction is downwards

<h3>c) Range</h3>

Substituting (7) in (2):

x=(97.22 m/s)(17.49 s) (11)

x=1700.99 m (12)

5 0
3 years ago
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