Answer:
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Step-by-step explanation:
We have been given a function
. We are asked to find the zeros of our given function.
To find the zeros of our given function, we will equate our given function by 0 as shown below:
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Now, we will factor our equation. We can see that all terms of our equation a common factor that is
.
Upon factoring out
, we will get:
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Now, we will split the middle term of our equation into parts, whose sum is
and whose product is
. We know such two numbers are
.




Now, we will use zero product property to find the zeros of our given function.




Therefore, the zeros of our given function are
.
Is 10 and 15 because they both have a value of .909
1/32
Monday 1/2
Tuesday 1/4
Wednesday 1/8
Thursday 1/16
Friday 1/32
All you have to do is multiply 1/2 to every one till you get to friday
8/5
I divided from both sides and flip the equation