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Sliva [168]
3 years ago
12

When correctly balanced using the smallest whole number coefficients, what is the coefficient of copper in the following formula

.....Cu+S8---->Cu2S
A. 1
B. 2
C. 8
D. 16
Chemistry
1 answer:
yan [13]3 years ago
4 0
The answer is 2. this makes the equation 2Cu + S8 —> Cu2S
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Consider the following reaction: Pb(NO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaNO3(aq)If you react an excess of Pb(NO3)2with 26.3 g
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Answer:

\large \boxed{84.7 \, \%}

Explanation:

Mᵣ:                          58.44      278.11

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m/g:                         26.3

1. Moles of NaCl

\text{Moles of NaCl} = \text{26.3 g NaCl} \times \dfrac{\text{1 mol NaCl}}{\text{58.44 g NaCl}} = \text{0.4505 mol NaCl}

(b) Moles of PbCl₂

\text{Moles of PbCl${_2}$} = \text{0.4505 mol NaCl} \times \dfrac{\text{1 mol PbCl${_2}$}}{\text{2 mol NaCl}} = \text{0.2253 mol PbCl${_2}$}

(c) Theoretical yield of PbCl₂

\text{Mass of PbCl${_2}$} = \text{0.2253 mol PbCl${_2}$} \times \dfrac{\text{278.11 g PbCl${_2}$}}{\text{1 mol PbCl${_2}$}} = \text{61.52 g PbCl${_2}$}

(d) Percent yield

\text{Percent yield} = \dfrac{\text{ actual yield}}{\text{ theoretical yield}} \times 100 \,\% = \dfrac{\text{52.1 g}}{\text{61.52 g}} \times 100 \, \% = \mathbf{84.7 \,\%}\\\\\text{The percent yield is $\large \boxed{\mathbf{84.7 \, \% }}$}

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B

Explanation:

Man with variety backgrounds

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Read 2 more answers
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